Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
i dont see ur pic
Step-by-step explanation:
pic?
I believe the answer would be DE is parallel to line segment FG
The original price would be $92.38
.25(73.90)=18.475
18.475+73.90 would be 92.38
2 ft 7 in
3 ft 11 in
6 ft 9 in
-----------------add
11 ft 27 in........and since 1 ft = 12 inches, then 27 inches = 2 ft 3 inches
so it would become : 13 ft 3 inches <==