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VARVARA [1.3K]
2 years ago
12

5/4x=3/2 how to solve it and find x

Mathematics
2 answers:
____ [38]2 years ago
4 0

Answer:

x=65

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    5/4*x-(3/2)=0

Simplify   —

           2

Equation at the end of step

1

:

  5         3

 (— • x) -  —  = 0

  4         2

STEP

2

:

           5

Simplify   —

           4

Equation at the end of step

2

:

  5         3

 (— • x) -  —  = 0

  4         2

STEP

3

:

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       4

     The right denominator is :       2

sertanlavr [38]2 years ago
3 0
X= 6/5 hope this helps
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jenna's rectangular garden borders a wall. she buys 80 ft of fencing. what are the dimensions of the garden that will maximize i
FrozenT [24]

Answer:

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

Step-by-step explanation:

Step 1:-

let 'x' be the length  and the 'y' be the width of the rectangle

given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is    2(x +y) = 80

                         x + y =40

                               y = 40 -x

now the area of the rectangle A = length X width

                                                  A = x y

substitute 'y' value in above A = x (40 - x)

                                              A = 40 x - x^2 .....(1)

<u>Step :2</u>

now differentiating equation (1) with respective to 'x'

                                      \frac{dA}{dx} = 40 -2x     ........(2)

<u>Find the dimensions</u>

<u></u>\frac{dA}{dx} = 0<u></u>

40 - 2x =0

40 = 2x

x = 20

and y = 40 - x = 40 -20 =20

The dimensions are x =20 and y=20

length = 20 and breadth = 20

<u>Step 3</u>:-

we have to find maximum area

Again differentiating equation (2) with respective to 'x' we get

\frac{d^2A}{dx^2} = -2

Now the maximum area A =  x y at x =20 and y=20

                                        A = 20 X 20 = 400

                                         

<u>Conclusion</u>:-

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

<u>verification</u>:-

The perimeter = 2(x +y) =80

                           2(20 +20) =80

                              2(40) =80

                              80 =80

8 0
3 years ago
Nick needs to raise at least $320 for his trip. He has $80 saved already, and he makes $40 per yard that he mows. Write and solv
Anestetic [448]

Answer: Nick must now at least 6 yards.

Step-by-step explanation:

Since Nick has $80 saved already, and he makes $40 per yard that he mows, thus can be put up in an equation as:

= 80 + 40y

where y = number of yards

Since Nick needs to raise at least $320 for his trip, the equation to solve this will be:

80 + 40x ≥ 320

40x ≥ 320 - 80

40x ≥ 240

x ≥ 240/40

x ≥ 6

Therefore, Nick must now at least 6 yards.

4 0
2 years ago
Y=-2x+1, y=-2/3x+5 solve using substitution
Bogdan [553]
<span>Y=-2x+1, y=-2/3x+5  
X= -3 and Y =7</span>
6 0
3 years ago
|3O+(-17)| I REALLY NEED TO KNOW PLZZZZZ
Soloha48 [4]

✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽

➷ 30 + 17

➷ 30 + -17

➷ = 13

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ May ♡

4 0
3 years ago
Read 2 more answers
How many even 5-digit numbers can be formed from the numbers 1, 2, 4, 7, 8 if no digit is repeated in a number? A. 72 B. 120 C.
katovenus [111]
Hello,

Let's place the last digit: it must be 2 or 4 or 8 (3 possibilities)

It remainds 4 digits and the number of permutations fo 4 numbers is 4!=4*3*2*1=24

Thus there are 3*24=72 possibilities.

Answer A

If you do'nt believe run this programm

DIM n(5) AS INTEGER, i1 AS INTEGER, i2 AS INTEGER, i3 AS INTEGER, i4 AS INTEGER, i5 AS INTEGER, nb AS LONG, tot AS LONG
tot = 0
n(1) = 1
n(2) = 2
n(3) = 4
n(4) = 7
n(5) = 8
FOR i1 = 1 TO 5
    FOR i2 = 1 TO 5
        IF i2 <> i1 THEN
            FOR i3 = 1 TO 5
                IF i3 <> i2 AND i3 <> i1 THEN
                    FOR i4 = 1 TO 5
                        IF i4 <> i3 AND i4 <> i2 AND i4 <> i1 THEN
                            FOR i5 = 1 TO 5
                                IF i5 <> i4 AND i5 <> i3 AND i5 <> i2 AND i5 <> i1 THEN
                                    nb = ((((n(i1) * 10) + n(i2)) * 10 + n(i3)) * 10 + n(i4)) * 10 + n(i5)
                                    IF nb MOD 2 = 0 THEN
                                        tot = tot + 1
                                    END IF
                                END IF
                            NEXT i5
                        END IF
                    NEXT i4
                END IF
            NEXT i3
        END IF
    NEXT i2
NEXT i1
PRINT "tot="; tot
END


7 0
3 years ago
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