You roll a six sided number cube and flip a coin. What is the probability of rolling a number greater than 5 and flipping heads.

Mathematics

2 answers:

Orlov [11]3 years ago

5 0

Answer:

1/6 for the number cube and 1/2 for coin

Step-by-step explanation:

weeeeeb [17]3 years ago

5 0

Answer:

1/12

Step-by-step explanation:

There are a total of 12 possible outcomes (numbers 1 through 6, and a heads or tails for each one). There is only 1 outcome where the number rolled is greater than 5 (has to be 6) and you flip a head.

So there is a 1 out of 12 chance.

1/12

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The distance between each base on a field is 90 ft. How far does a catcher have to throw the ball from home plate to second base

Gnoma [55]

Step-by-step explanation:

A baseball field is in the shape of a square (or diamond). Home plate and second base are opposite corners of each other. So the distance is equal to the diagonal of the square.

Use Pythagorean theorem to find the diagonal, or use properties of a 45-45-90 triangle.

Using Pythagorean theorem:

c² = a² + b²

c² = (90 ft)² + (90 ft)²

c = 90√2 ft

c ≈ 127 ft

7 0

3 years ago

A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4

Vladimir79 [104]

Answer:

The time interval when $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

$V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)$

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

$V_Q(t) \geq 60$ between $0 \leq t \leq 4$

The schematic free body graphical representation of the above illustration was attached in the file below and the point when $V_Q(t) \geq 60$ is at 4 is obtained in the parabolic curve.

So, $V_Q(t) \geq 60$ is at $1.866 \leq t \leq 3.519$

Taking the integral of the time interval in order to determine the distance; we have:

distance = $\int\limits^{3.519}_{1.866} {V_Q(t)} \, dt$