A line has a slope of 3 and a y-intercept of 4. What is the equation of the line in

Mathematics

2 answers:

mash [69]2 years ago

5 0

Answer:

Compare with the normal equation of a line

Kipish [7]2 years ago

4 0

Answer:

General equation of a line:

$y = mx + b$

m is the slope

b is the y-intercept

Therefore, answer is:

${ \boxed{ \boxed{y = 3x + 4}}}$

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Fill in each blank with one of the three phrases: is less than, is equal to, or is greater than.

Kazeer [188]

✧･ﾟ: *✧･ﾟ:* Answer: *:･ﾟ✧*:･ﾟ✧

✅ 1,742 x 1.000 > 1,742

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2 years ago

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The theater department charged $5 per ticket for admission to the fall play, My Fair Lady. Additionally, they asked for a donati

barxatty [35]

Answer:

$(400+80x)

Step-by-step explanation:

We are required to find the total income on Friday Night

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2 years ago

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$