A town orchestra needs 3 new flute players and 4 new trumpet players. 8 flutists and 11 trumpeters try out, then the orchestra should select 3 flutists from 8 and 4 trumpeters form 11.

They can choose 3 flutists from 8 in

$C_8^3=\dfrac{8!}{3!(8-3)!}=\dfrac{8!}{3!\cdot 5!}=\dfrac{1\cdot 2\cdot 3\cdot 4\cdot 5\cdot 6\cdot 7\cdot 8}{1\cdot 2\cdot 3\cdot 1\cdot 2\cdot 3\cdot 4\cdot 5} =56$ ways.

They can choose 4 flutists from 11 in

$C_{11}^4=\dfrac{11!}{4!(11-4)!}=\dfrac{11!}{4!\cdot 7!}=\dfrac{1\cdot 2\cdot 3\cdot 4\cdot 5\cdot 6\cdot 7\cdot 8\cdot 9\cdot 10\cdot 11}{1\cdot 2\cdot 3\cdot 4\cdot 1\cdot 2\cdot 3\cdot 4\cdot 5\cdot 6\cdot 7} =330$ ways.

Use the product rule: 56·330=18480 ways for conductor to choose his new members.

3 0

3 years ago

Equation of the line (4,1) and (8,5)

Hatshy [7]

Answer:

when in doubt, the answer is 0

Step-by-step explanation:

5 0

3 years ago

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Solve the system of equations down below Y-15=3x<br> -2+5y=-3

jenyasd209 [6]

Answer:

Step-by-step explanation:

-5(y-15=3x) = -5y+75=-15x

add 15x to both sides and subtract 75 to both side

-5y+15x=-75

5y-2x=-3

13x=-78

and then both side divide by 13

x=-6

y-15=3(-6)

y-15=-18

Y= (-18) - 15 = -3

y=-3

and the answer will be (-6,-3)

hope that help you

7 0

3 years ago

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