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Tanya [424]
2 years ago
5

If p(x)=-2x-4 and p(x)=6x ,find x. PLEASE ANSWER!

Mathematics
1 answer:
Alborosie2 years ago
5 0

Answer:

x = -0.5

Step-by-step explanation:

p(x) = -2x - 4 = 6x

-4 = 8x

x = -0.5

Topic: Functions + Simultaneous equations

If you would like to venture further into mathematics, you can check out my Instagram page (learntionary) where I post notes and mathematics tips. Thanks!

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A painter needs to buy a ladder in order to paint a wall that is 18 feet high. In order to ensure the ladder does not fall it ne
trapecia [35]

Answer:

222! thats your answer!

Step-by-step explanation:

6 0
3 years ago
How do we find the quadratic equation in standard form with the given roots of -1/3, 5?
Olin [163]
I think this is the answer. Because it doesn’t mention a leading coefficient but it’s a quadratic function so it would be
1(x-1/3)(x-5) and that should be your answer. The simplified version is down below

8 0
3 years ago
Quinton bought x number of shares for p dollars and paid a 0.5% commission. He sold the stock for y dollars and paid a flat fee
Ksju [112]

Answer:

y-(0.05xp+7)

Step-by-step explanation:-

As per the statement:

Quinton bought x number of shares for p dollars and paid a 0.5% commission

⇒0.05xp

It is also given that: He sold the stock for y dollars and paid a flat fee of $7.

⇒y-7

then;

Net proceeds is given as:

y-7-0.05xp = y-(0.05xp+7)

Therefore, Quinton's net proceeds algebraically is y-(0.05xp+7)

4 0
3 years ago
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garri49 [273]

Answer:

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8 0
3 years ago
Aya = a1 + (n - 1)d
Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

a_{26}=67

Hence, option A is true.

Step-by-step explanation:

Given

  • a₁ = -33
  • d = 4

An arithmetic sequence has a constant difference 'd' and is defined by

a_n=a_1+\left(n-1\right)d

substituting a₁ = -33 and d = 4 in the nth term of the sequence

a_n=-33+\left(n-1\right)4

\:a_n=-33+4n-4

a_n=4n-37

Thus, the nth term of the sequence is:

a_n=4n-37

now substituting n = 26 in the nth term to determine the 26th term of the sequence

a_n=4n-37

a_{26}=4\left(26\right)-37

a_{26}=104-37

a_{26}=67

Therefore, the 26th term of an arithmetic sequence is:

a_{26}=67

Hence, option A is true.

7 0
2 years ago
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