Answer:
S varies partly directly as M and Q.
S=C.
S=KMQ+C.
For the first one...
speed=80,m=220,Q=30.
80=K20×30+C.
80=600K+C......(I).equation one.
For the second one....
speed=60,m=300,Q=40.
60=K300×40+C.
60=12000K+C.....(ii). equation two.
Minus eqtn(I) from eqtn(ii).
80=600K+C.
- 60=12000K+C.
K=0.01754~0.018.
Substitute K=0.018 into eqtn(I).
80=600K+C
80=600×0.018+C.
80=10.8+C.
C=80-10.8=69.2.
The relation is S=0.018MQ+69.2
when speed is 100 and mass is 250 find the volume.
100=0.018×250×Q+69.2.
100=4.5Q+69.2.
4.5Q=100-69.2
4.5Q=30.8.
Q=30.8/4.5.
Q=6.8~7litres.
I don't know about the first one but the second one is 34.9°. It would be that because are right angles add up to 90° and if you subract 55.1 and 90 it would equal 34.9. But this rule only works on right angles.
Which set of ordered pairs contains only points that are on the graph of the function y=12-3×?
Answer:
let t = number of three-point shots
let f = number of free throw shots
Step-by-step explanation:
t + f = 9 (he made a total of 9 shots altogether)
3t + 1f = 23 (number of shots multiplied by their point value)
substitution method: t = 9 - f
3(9 - f) + f = 23
27 - 3f + f = 23
-2f = -4
f = 2
find 't': t + 2 = 9
t = 7
the horizontal line must have the same y coordinate so y=14
