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Degger [83]
3 years ago
13

Use distributive property to rewrite 6(11+x)=

Mathematics
2 answers:
mamaluj [8]3 years ago
8 0
Hey there!
The distributive property is defined as:
a(b+c) = ab+ac
Using this property, we can solve this problem.
Because it's a times c, we first multiply 6 by 11 to get 66, and then 6 by x to get 6x. Therefore, our answer is:
66 + 6x
Hope this helps!
Lady_Fox [76]3 years ago
4 0
6 times 11 + 6 times x
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Let the vector v have an initial point at (3,−2) and a terminal point at (3,−7). Determine the components of vector v
kiruha [24]

Answer:

(0,-5)

Step-by-step explanation:

Terminal minus initial. (3-3, -7+2) = (0,-5)

3 0
2 years ago
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Calcula en cada caso las restantes razones trigonométricas de un angulo agudo si se conoce que:
olchik [2.2K]
A) cos a = (√22)/5; tan a = (√66)/22
B) sin a = (2√2)/3; tan a = 2√2
C) sin a = (√30)/6; cos a = (√6)/6
D) sin a = 3/5; tan a = 3/4
E) sin a = (5√26)/26; cos a = (√26)/26
F) sin a = 3/5; tan a = 3/4

Explanation
The ratio for sine is opposite/hypotenuse.  This means the side opposite the angle is √3 and the hypotenuse is 5.  Using the Pythagorean theorem to find the adjacent side,
(√3)² + A² = 5²
3+A² = 25
A² = 22
A=√22
This means that cos a = adjacent/hypotenuse = (√22)/5 and tan a = opposite/adjacent = (√3)/(√22) = (√66)/22.
B)  The ratio for cosine is adjacent/hypotenuse; this means the side adjacent to the angle is 1 and the hypotenuse is 3.  Using the Pythagorean theorem to find the side opposite the angle (p),
1² + p² = 3²
1+p² = 9
p² = 8
p=√8 = 2√2
This means that sin a = opposite/hypotenuse = (2√2)/3 and tan a = opposite/adjacent = (2√2)/1 = 2√2.
C) The ratio for tangent is opposite/adjacent; this means that the side opposite the angle is √5 and the side adjacent the angle is 1.  Using the Pythagorean theorem to find the hypotenuse,
(√5)²+1² = H²
5+1=H²
6=H²
√6 = H
This means that sin a = opposite/hypotenuse = (√5)/(√6) = (√30)/6 and cos a = adjacent/hypotenuse = 1/(√6) = (√6)/6.
D)  The ratio for cosine is adjacent/hypotenuse; this means that the side adjacent the angle is 4 and the hypotenuse is 5.  Using the Pythagorean theorem to find the side opposite the angle, p:
4²+p²=5²
16+p²=25
p²=9
p=3
This means that sin a = opposite/hypotenuse = 3/5 and tan a = opposite/adjacent = 3/4.
E)  The ratio for tangent is opposite/adjacent;; this means that the side opposite the angle is 5 and the side adjacent the angle is 1.  Using the Pythagorean theorem to find the hypotenuse,
5²+1²=H²
25+1=H²
26=H²
√26 = H
This means that sin a = opposite/hypotenuse = 5/(√26) = (5√26)/26 and cos a = adjacent/hypotenuse = 1/(√26) = √26/26.
F) 0.8 = 8/10; The ratio for cosine is adjacent/hypotenuse.  This means that the side adjacent the angle is 8 and the hypotenuse is 10.  Using the Pythagorean theorem to find the side opposite the angle, p:
8²+p² = 10²
64+p² = 100
p² = 36
p=6
This means that sin a = opposite/hypotenuse = 6/10 = 3/5 and tan a = opposite/adjacent = 6/8 = 3/4.
6 0
3 years ago
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3x +12 =90 what is x
castortr0y [4]

Answer:

x=26

Step-by-step explanation:

3x +12 =90

subtract 12 from each side

3x=78

divide 3 from each side

x=26

3 0
2 years ago
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It takes 1 1/2 hours to fill 1/2 of a tank how long will it take to fill 2 tanks completely
Likurg_2 [28]

Answer:

15

Step-by-step explanation:

hope this helps

4 0
2 years ago
use the line graph to answer the question 9 and 10 how much did the temperature change from Sunday High to Mondays High ? what w
Marizza181 [45]

Answers:

<em>How much did the temperature change from Sunday High to Mondays High?</em>

Change = 4 °C

<em>What was the difference between the high temperatures on Friday and Wednesday?​</em>

Difference = 10 °C

Explanation:

Taking into account the graph, we get that the high temperature each day is:

Sunday: -10°C

Monday: -6 °C

Tuesday: - 4 °C

Wednesday: -6 °C

Thursday: 0 °C

Friday: 4 °C

Saturday: -2 °C

So, the change from Sunday High to Mondays High can be calculated as:

Change = Monday - Sunday

Change = -6 °C - (- 10 °C)

Change = -6 °C + 10 °C

Change = 4 °C

In the same way, the difference between the high temperatures on Friday and Wednesday can be calculated as:

Difference = Friday - Wednesday

Difference = 4 °C - (-6 °C)

Difference = 4 °C + 6 °C

Difference = 10 °C

Therefore, the answers are:

<em>How much did the temperature change from Sunday High to Mondays High?</em>

Change = 4 °C

<em>What was the difference between the high temperatures on Friday and Wednesday?​</em>

Difference = 10 °C

6 0
1 year ago
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