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Katena32 [7]
2 years ago
12

I need help please it’s a test

Mathematics
2 answers:
Elden [556K]2 years ago
8 0

Answer:

Set b

Step-by-step explanation:

IRISSAK [1]2 years ago
8 0
The answer is B for that question
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For a function to begin to qualify as differentiable, it would need to be continuous, and to that end you would require that a is such that

\displaystyle\lim_{x\to0^-}g(x)=\lim_{x\to0^+}g(x)\iff\lim_{x\to0}ax=\lim_{x\to0}x^2-3x

Obviously, both limits are 0, so g is indeed continuous at x=0.

Now, for g to be differentiable everywhere, its derivative g' must be continuous over its domain. So take the derivative, noting that we can't really say anything about the endpoints of the given intervals:

g'(x)=\begin{cases}a&\text{for }x0\end{cases}

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\displaystyle\lim_{x\to0^-}g'(x)=\lim_{x\to0^+}g'(x)\iff\lim_{x\to0}a=\lim_{x\to0}2x-3

from which it follows that a=-3.

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How do you sovle this equation by factoring 7x^2+7x=0
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