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2 years ago

Negative one-sixth of a number is less than -9. write an inequality.

Mathematics

1 answer:

sladkih [1.3K]2 years ago

3 0

Answer:

-1/6 n < -9

Step-by-step explanation:

Negative one-sixth of a number

-1/6 n

is less than -9

-1/6 n < -9

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How do I solve this?

ohaa [14]

Answer:

Step-by-step explanation:

$x=e^{2t}-1\\y=e^t\\squaring\\\\y^{2}=e^{2t}\\Hence ~x=y^{2}-1$

5 0

3 years ago

The point P(21,35) is on the terminal side of an angle in standard position. What is the distance from P to the origin?

Ira Lisetskai [31]

Answer:

The distance from P to origin is approximately 40.82 units.

Step-by-step explanation:

We are given the following in the data:

The point P(21,35)

We have to find the distance of point P from the origin.

Coordinates of origin: (0,0)

Distance formula:

$(x_1,y_1),(x_2,y_2)\\\\d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

Putting the values, we get,

$(21,35), (0,0)\\\\d = \sqrt{(0-21)^2 + (0-35)^2} = \sqrt{1666} = 7\sqrt{34} \approx 40.82\text{ units}$

The distance from P to origin is approximately 40.82 units.

7 0

3 years ago

It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando

notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, $\overline x_1$ = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, $\overline x_2$ = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀: $\overline x_1$ = $\overline x_2$

The alternative hypothesis, Hₐ: $\overline x_1$ ≠ $\overline x_2$

The pooled variance, $S_p^2$ , is given as follows;

$S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}$

Therefore, we have;

$S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682$

The test statistic is given as follows;

$t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}$

Therefore, we have;

$t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176$

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0

2 years ago

Can you help please?

harkovskaia [24]

Step-by-step explanation:

Mechanical advantage can be defined using distances:

Mechanical advantage = input distance / output distance

Or it can be defined using forces:

Mechanical advantage = output force / input force

Solving for the output force:

Output force = mechanical advantage × input force

Plugging in values:

Output force = 2.2 × 202 N

Output force = 444.4 N

3 0

2 years ago

Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the accou

storchak [24]

Hello!

Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the account and does not withdraw any money. What is the balance of Lynne's account in 5years

Data:

P = 35000

r = 4% = 0,04

n = 4

t = 5

P' = ?

I = ?

We have the following compound interest formula

$P' = P*(1+\dfrac{r}{n})^{nt}$