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klasskru [66]
3 years ago
9

How to solve 167<6+7(2-7r)

Mathematics
1 answer:
Leona [35]3 years ago
8 0
167<6+7(2-7r)167<6+14-49r
167-6-14<-48r
147<-49 r
r >-3
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Which answer best describes the complex zeros of the polynomial function?
marysya [2.9K]

<u>Answer-</u>

<em>D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.</em>

<u>Solution-</u>

The given polynomial is,

f(x)=x^3-x^2+6x-6

The zeros of the polynomials are,

\Rightarrow f(x)=0

\Rightarrow x^3-x^2+6x-6=0

\Rightarrow x^2(x-1)+6(x-1)=0

\Rightarrow (x^2+6)(x-1)=0

\Rightarrow (x^2+6)=0,(x-1)=0

\Rightarrow x=\sqrt{-6},\ x=1

\Rightarrow x=1,\ \pm \sqrt6i

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1

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3 years ago
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frosja888 [35]

Answer:

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2 years ago
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The function A(b) relates the area of a trapezoid with a given height of 14 and one base length of 5 with the length of its othe
stellarik [79]
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The difference of two complementary angles is 20. Find the measure of each angle​
stich3 [128]

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Step-by-step explanation:

Let one angle be x.

It's complementary angle is = (90 - x)°

According to the question ,

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so

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2 years ago
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