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2 years ago

9

How to solve 167<6+7(2-7r)

1 answer:

Leona [35]2 years ago

8 0

167<6+7(2-7r)167<6+14-49r
167-6-14<-48r
147<-49 r
r >-3

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2k^2-5k-18=0 what is both of the values of k? plz help!!! 15 pts!!!

ddd [48]

To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.

jk=ac and j+k=b

The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...

2k^2-5k-18=0

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so k=-2 and 9/2

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3 years ago

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zzz [600]

Answer:

$y=-5x+7$

Step-by-step explanation:

step 1

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The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

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substitute

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step 2

we know that

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substitute in the linear equation and solve for b

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3 years ago

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larisa86 [58]

Plug in -1 for x
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zubka84 [21]

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