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Ksenya-84 [330]
3 years ago
7

Bryan runs 2 miles every 40 minutes. At this rate, how many minutes did Bryan run if he ran 8 miles?

Mathematics
2 answers:
andreev551 [17]3 years ago
6 0
160 minutes also known as 2 hours and 40 minutes
s2008m [1.1K]3 years ago
4 0

2 ÷ 40 = 20

so

1 mile = 20 minutes

20 minutes × 8 miles = 160 minutes

160 minutes into hours and minutes = 2 hours and 40 minutes

Answer:

160 minutes or 2 hours and 40 minutes

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WHICH OF THE FOLLOWING REPRESENTS A NON LINEAR EQUATION
sertanlavr [38]

Answer:

y = 3/x

Step-by-step explanation:

3 0
2 years ago
Because of the commutative property of multiplication, it is true that
rewona [7]

Answer:

It is Commutative

Step-by-step explanation:

An operation ∆ is said to be Commutative if a∆b=b∆a ∀ a,b ∈ ℝ.

Given the operation ∆ defined by:

a∆b=a X b

a=\frac{3}{4}, b=4

a∆b=\frac{3}{4}X4

=\frac{3X4}{4}=3

Similarly, for the right hand side.

(\frac{4}{3})^{-1}=\frac{3}{4}

Therefore:

b∆a=4X \frac{3}{4}

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These are the two ways of solving this problem and we have in fact shown that the operation is commutative as:

a∆b=b∆a=3

3 0
3 years ago
A general purpose variable that can hold most other types of variable values is :
natali 33 [55]
This is known as a variant!
3 0
3 years ago
Z to the power of 2 =1
stiv31 [10]

That would be written as:

z^{2} = 1


And the step-by-step equation would be:

z^{2} = 1 → we take the 2 to the right side of the equation and do the IO*

z = \sqrt{1} →we solve for \sqrt{1}

z = 1 → final answer


*Ps - IO is not an existing term and stands for inverse operation. In this case, because when we take to 2 to the right side of the equation (the 2 is a power) it'll have to turn into a square root (because exponents and roots are inverse operations)



Hope it helped,



BioTeacher101

3 0
3 years ago
The population of bacteria in a Petri Dish is growing at a rate of 0.8t^3 + 3.5 thousand per hour. Find the total increase in ba
aliina [53]

Answer:

p=9900\\ bacterias in the initial two hours

Step-by-step explanation:

the growing rate is given by the ecuation

p(t)=0.8(t)^{3} +3.5 thousand per hour

for t=2 we have

p(2)=0.8(2)^{3} +3.5 = 9.9 thousand

p=9900\\ bacterias

In two hours we have 9900 bacterias

3 0
3 years ago
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