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3 years ago

Divide 560 in the ratio of 3:4

Mathematics

2 answers:

bonufazy [111]3 years ago

4 0

Answer:

3:4

3/7*560

=240

4/7*560

=320

4:3=240 & 320

Step-by-step explanation:

goldenfox [79]3 years ago

3 0

Answer:

560 multiplied by $\frac{3}{4}$ equals 420

Step-by-step explanation:

$560 * \frac{3}{4} = 140 * 3 = 420$ .

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The following sequence is an arithmetic sequence what comes next ? 7,___,17

ipn [44]

Since this is an arithmetic sequence, you can conclude that the addition to the number is constant.

Let x = the number asked

k = constant number added to the sequence

7 + k = x

x + k = 17

Solve the system of equation:

7 + k + k = 17

7 + 2k = 17

2k = 10

k = 5

Therefore, the missing number is 12 (7 + 5).

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3 years ago

Find the first five terms of the sequence in which a1 = 6 and an = –3an – 1 – 12, if n ≥ 2.

maxonik [38]

Answer:

Step-by-step explanation:

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3 years ago

Ellie’s parents travel down to see her and have a look at the property. When they set off, the mileage on the car reads 46,817 a

Nitella [24]

46817-47411=-594
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594 mi

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3 years ago

Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m

GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

$d=\sqrt{\frac{3h}{2} }$

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

$d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)$

For Addison h=85(1/3)

$d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)$

Subtracting both distances we get

$8\sqrt{2}-6\sqrt{2} =2\sqrt{2}$

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

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2 years ago

Use these functions to answer the questions.

Elenna [48]

Part A
We have $f\left(x\right)=\left(x+3\right)^2-1$ . To solve for the x-intercept, we set f(x) equal to 0. That is
$\left(x+3\right)^2-1=0$

$\left(x+3\right)^2=1$

Take the square root of both sides,
$x+3=1$

$x=-2$

The x-intercept is (-2,0).

To solve for the y-intercept, we set x=0. That is
$y=\left(0+3\right)^2-1=3^2-1=9-1=8$

The y-intercept is (0, 8)

The coordinates of the optimum point are actually the vertex which can be easily seen from the vertex form equation given above. The minimum point is (-3, -1).

Part B.
We have $g\left(x\right)=-2x^2+8x+3$ .
Factor out -2
$=-2\left(x^2-4x\right)+3$

Complete the square
$=-2\left(x^2-4x+4\right)+3-2\left(4\right)$

Simplify
$g(x)=-2\left(x-2\right)^2-5$

Part C
We have $h\left(t\right)=-16t^2+28t$ .
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3 years ago