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steposvetlana [31]
2 years ago
11

If triangle ABC is isosceles and triangle DBE is equilateral what is the measure of angle C

Mathematics
1 answer:
luda_lava [24]2 years ago
6 0

Answer:

43°

Step-by-step explanation:

For triangle ABC:

A = C so all we need to do is to calculate the value of B

The measure of angle ABD is given as 17° so the measure of angle EBC must be 17° as well

Since DBE is an equilateral triangle angle is DBE = 60°

17 + 17 + 60 = 94 this is the measure of angle B

The sum of interior angles in a triangle is equal to 180

A + B + C = 180

A + C + 94 = 180

A + C = 86 since A = C we divide 86 by 2

C = 43°

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nalin [4]

Answer:

$0.67

Step-by-step explanation:

Divide 8(dollars) by 12 (donuts) and you get  0.66666666666666666666666666666667

But, round it and you get .67

4 0
3 years ago
What is the exact value of tan 30° ? Enter your answer, as a simplified fraction, in the box.
Romashka [77]
Hmmm if you don't have a Unit Circle, this is a good time to get one, many you can find online.  Anyhow, check your unit circle for cos(30°) and sin(30°).

\bf tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\qquad \qquad tan(30^o)=\cfrac{sin(30^o)}{cos(30^o)}
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tan(30^o)=\cfrac{\quad \frac{1}{2}\quad }{\frac{\sqrt{3}}{2}}\implies tan(30^o)=\cfrac{1}{2}\cdot \cfrac{2}{\sqrt{3}}\implies tan(30^o)=\cfrac{1}{\sqrt{3}}
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\stackrel{\textit{and now if we rationalize the denominator}}{\cfrac{1}{\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}}\implies \cfrac{\sqrt{3}}{(\sqrt{3})^2}\implies \cfrac{\sqrt{3}}{3}}
8 0
3 years ago
Read 2 more answers
Evaluate the following limit:
Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

        \large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

<h3>Way 1:</h3>

By comparison of infinities:

We first expand the binomial squared, so we get

                         \large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

<h3>Way 2</h3>

Dividing numerator and denominator by the term of highest degree:

                            \large\displaystyle\text{$\begin{gathered}\sf L  = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4  }{x^{3}-5  }  \end{gathered}$}\\

                                \ \  = \lim_{x \to \infty\frac{\frac{x^{4}  }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} }    }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}}   }  }

                                \large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} }  }{\frac{1}{x}-\frac{5}{x^{4} }  }  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

5 0
2 years ago
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REY [17]

P=45

How do I Know that?

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3 years ago
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m_a_m_a [10]

Answer:

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Step-by-step explanation:

56 ÷ 7 = 8

7 0
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