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lions [1.4K]
3 years ago
13

If you place a 39-foot ladder against the top of a 34-foot building, how many feet will

Mathematics
2 answers:
netineya [11]3 years ago
6 0

Answer: 19.1ft

Step-by-step explanation:

zmey [24]3 years ago
6 0

Answer:

19.1ft

Step-by-step explanation:

I know this because I did it before lol

Hope it helps!

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Find the value of y so that line is passing through two points
Alenkinab [10]
Slope of a line passing through two given points 
= (y2-y1)/(x2-x1)

For m=3, and substituting coordinates,
3=(1-y)/(4-1)
solve for  y
1-y=3*3=9
y=1-9=-8

Answer: y=-8
6 0
3 years ago
To add integers with the same sign
Mariana [72]

Arithmetic

-3-2=5

because

-3-2

=

-3 + -2

3 negatives + 2 negatives = 5 negatives

5 0
3 years ago
Read 2 more answers
Solve the system of linear equations using linear combination.
brilliants [131]
3a + 6b = 45
2a - 2b = -12....multiply by 3
----------------
3a + 6b = 45
6a - 6b = - 36 ...(result of multiplying by 3)
---------------add
9a = 9
a = 1

3a + 6b = 45
3(1) + 6b = 45
3 + 6b = 45
6b = 45 - 3
6b = 42
b = 7

solution is : (1,7)
6 0
3 years ago
Read 2 more answers
A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow
Mrrafil [7]

Answer:

\displaystyle \frac{54}{5405}.

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

\displaystyle \left(50\atop 5\right) = 2,118,760.

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

\displaystyle \left( 28\atop 2\right) = 378.

Number of ways to choose 3 green candies out of a batch of 8:

\displaystyle \left(8\atop 3\right)=56.

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168.

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}.

3 0
3 years ago
Which of these shows the result of using the first equation to substitute for y in the second equation then combing like terms
AnnyKZ [126]

2x + 3y = 55

2x + 3(3x) = 55

2x + 9x = 55

11x = 55

\frac{11x}{11}  =  \frac{55}{11}

x=5

8 0
3 years ago
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