Question
Student presentation concepts from another source
Letitia - a step-by-step process of breaking down glucose into energy
Mana - repeating process of the steps of the cell division, going from interphase to division, and back to interphase.
Paul - a series of organisms that show similar characteristics and compare them to those that do not
Which best describes the SmartArt graphic layout each student should use?
Answer:
Letitia would use a process, Maria would use a cycle, and Paul would use a relationship.
Explanation:
Letita's assignment requires her to show how glucose can be broken down into energy, this requires a series of steps in s linear fashion, meaning it would be best suited to a process-style diagram.
Marta's project involves showing the steps of the cell cycle: the clue is in the name. This process is not linear, and instead repeats itself, meaning it fits to a cycle diagram (i.e. a circular diagram)
Paul is comparing and contrasting different organisms. Therefore, he should use a relationship diagram to show shared characteristics as well as features that differ.
The CPU performs basic arithmetic, logic, controlling, and input/output (I/O) operations specified by the instructions in the program. This contrasts with external components such as main memory and I/O circuitry, and specialized processors such as graphics processing units (GPUs).
Answer:
Program source code found in explaination
Explanation:
Recursive int function of the asked question.;
int productOfOdds(int array[],int length) {
int product=1;
if(length==0)
return -1;
else if(length==1) {
if(array[length-1]%2!=0)
return array[length-1];
else
return 1;
}
else {
product=productOfOdds(array,--length);
if(array[length]%2!=0) {
product=product*array[length];
}
}
return product;
}
Answer:
The answer to this question can be defined as follows:
Explanation:
Its Permute-with-all method, which doesn't result in a consistent randomized permutation. It takes into account this same permutation, which occurs while n=3. There's many 3 of each other, when the random calls, with each one of three different values returned and so, the value is= 27. Allow-with-all trying to call possible outcomes as of 3! = 6
Permutations, when a random initial permutation has been made, there will now be any possible combination 1/6 times, that is an integer number m times, where each permutation will have to occur m/27= 1/6. this condition is not fulfilled by the Integer m.
Yes, if you've got the permutation of < 1,2,3 > as well as how to find out design, in which often get the following with permute-with-all chances, which can be defined as follows:
Although these ADD to 1 none are equal to 1/6.
