Plssssss shelp meeeeeee

Find the midsegment of triangle ABC so that it is parallel to side BC and label it as segment EG on the graph coordinate of E: _

Sholpan [36]

Answer:

Coordinate of E: (-2,3) Coordinate of G: (2.5, 1.5)

Step-by-step explanation:

You first have to find the midpoints of AC and AB.

AC X coordinate:

X1+X2/2

Substitute the x points of AC in

1+(-5)/2=-2

AC Y coordinate:

Y1+Y2/2=3

Substitute the y points of AC in

5+1/2=3

You do the same thing with the AB line. I am pretty sure this works and I hope this helps!

5 0

2 years ago

Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1

elena-s [515]

Answer:

a) $P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

b) $P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

c) $0.75 =\frac{0.83}{1+e^{-0.2n}}$

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

d) If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

$P(n) = \frac{0.83}{1+e^{-0.2t}}$

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

$P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536$

So the number of correct reponses after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

$P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666$

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

$0.75 =\frac{0.83}{1+e^{-0.2n}}$

And we can rewrite this expression like this:

$1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}$

$e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}$

Now we can apply natural log on both sides and we got:

$ln e^{-0.2n} = ln (\frac{8}{75})$

$-0.2 n = ln(\frac{8}{75})$

And then if we solve for t we got:

$n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials$

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

$lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83$

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

5 0

3 years ago

24+ 24 Pts bbbbbbb.

Valentin [98]

Answer:

All equally important without physical health having social health might be harder since you might not be able to interact as well because of illness which would then affect mental. Without mental health your social and physical health would deteriorate and without social health your mental then physical health would deteriorate we need a balanced amount of all of these

Step-by-step explanation:

All equally important without physical health having social health might be harder since you might not be able to interact as well because of illness which would then affect mental. Without mental health your social and physical health would deteriorate and without social health your mental then physical health would deteriorate we need a balanced amount of all of these

8 0

3 years ago

I WILL GIVE YOU BRAINLIEST ,5 STARS⭐, AND THANKS❤️. (P.S. AT LEAST TWO PEOPLE GIVE ANSWER SO I CAN GIVE BRAINLIEST)

Crank

Answer:

0.002

Step-by-step explanation:

cuz

5 0

3 years ago

Instructions: Find the missing side lengths. Leave your answers as radicals in simplest form.

sweet-ann [11.9K]