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3 years ago

F(x)=3x^3-12x^2+9x what the factor

Mathematics

2 answers:

Veseljchak [2.6K]3 years ago

7 0

Answer:

3x(x - 1)(x - 3)

Step-by-step explanation:

the sum of the coefficients = 3 - 12 + 9 = 0

hence x = 1 is a root of f(x) and (x - 1) is a factor

dividing 3x³ - 12x² + 9x gives

f(x) = (x - 1)(3x² - 9x)

= (x - 1)3x(x - 3) = 3x(x - 1)(x - 3) ← in factored form

alexandr1967 [171]3 years ago

6 0

Answer:

f(x) = 3x(x-1)(x-3)

Step-by-step explanation:

f(x) = 3x³-12x²+9x = 3x(x²-4x+3) =

= 3x(x²-x-3x+3) = 3x[x(x-1)-3(x-1)] =

= 3x[(x-1)(x-3)] = 3x(x-1)(x-3)

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F(x)=3x^3-12x^2+9x what the factor​

F(x)=3x^3-12x^2+9x what the factor