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hodyreva [135]
3 years ago
15

F(x)=3x^3-12x^2+9x what the factor​

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
7 0

Answer:

3x(x - 1)(x - 3)

Step-by-step explanation:

the sum of the coefficients = 3 - 12 + 9 = 0

hence x = 1 is a root of f(x) and (x - 1) is a factor

dividing 3x³ - 12x² + 9x gives

f(x) = (x - 1)(3x² - 9x)

    = (x - 1)3x(x - 3) = 3x(x - 1)(x - 3) ← in factored form

alexandr1967 [171]3 years ago
6 0

Answer:

f(x) = 3x(x-1)(x-3)

Step-by-step explanation:

f(x) = 3x³-12x²+9x = 3x(x²-4x+3) =

= 3x(x²-x-3x+3) = 3x[x(x-1)-3(x-1)] =

= 3x[(x-1)(x-3)] = 3x(x-1)(x-3)

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What is the range of this graph
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[0,12]

Step-by-step explanation:

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3 years ago
There are 20 student desks
liq [111]

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3 years ago
Solve the following initial-value problem:<br><br> (ex+y)dx+(3+x+yey)dy=0, y(0)=1<br><br> 0=
alex41 [277]

Answer:

e^x+xy+3y+(y-1)e^y=4

Step-by-step explanation:

Given that

(e^x+y)dx+(3+x+ye^y)dy=0

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N=3+x+ye^y

We know that

M dx + N dy=0 will be exact if

\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}

So

\frac{\partial M}{\partial y}=1

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it means that this is a exact equation.

\int d\left(e^x+xy+3y+(y-1)e^y\right)=0

Noe by integrating above equation

e^x+xy+3y+(y-1)e^y=C

Given that

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C=4

So the our final equation will be

e^x+xy+3y+(y-1)e^y=4

3 0
3 years ago
You deposit $400 in an account earning 2% interest compounded annually. How much will you have in the account in 20 years?
iVinArrow [24]

Answer:

Approximately $594.38

Step-by-step explanation:

Use the formula: y = a(1 + r)^t
a is the initial amount
r is the percent of interest in decimal form
t is the time in years
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Substitute the values given in the problem into the equation:
400(1+0.02)^20
Use a calculator or solve manually
Around 594.38

6 0
2 years ago
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