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lapo4ka [179]
3 years ago
15

Function g is a transformation of the parent exponential function. Which statements are true about function g?

Mathematics
1 answer:
Elan Coil [88]3 years ago
3 0

Answer:

function g is positive over (-∞, ∞)

function g has a y-intercept of (0,4)

function g decreasing over the interval (-∞, 0)

Step-by-step explanation:

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I WILL GIVE BRAINLIEST AND THANKS SOLVE THE QUADRATIC EQUATION
laiz [17]

Answer:

x = -0.907, 2.57

Step-by-step explanation:

Quadratic Formula: x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}

Since we are given <em>a</em> = 3, <em>b</em> = -5, and <em>c</em> = -7 from our quadratic, we simply use the Quadratic Formula:

Step 1: Plug in variables

x=\frac{-(-5)+/-\sqrt{(-5)^2-4(3)(-7)} }{2(3)}

Step 2: Solve

x=\frac{5+/-\sqrt{25+ 84} }{6}

x=\frac{5+/-\sqrt{109} }{6}

Step 3: Evaluate for decimals

You should get x = -0.906718 and 2.57338 as your answers.

3 0
3 years ago
Read 2 more answers
Trey runs 7 miles in 50 minutes. at the same rate, how many miles would he run in 75 minutes?
slava [35]

He can run 10.5 miles in 75 minutes

8 0
3 years ago
A rectangular fish tank has a base that is 7 inches
aivan3 [116]

Answer:

210 in^3

Step-by-step explanation:

7x5x6 = 210 cubic inches

8 0
3 years ago
Does anyone know how to do this? I’m confused
nikklg [1K]

Answer:

cos(θ)

Step-by-step explanation:

Para una función f(x), la derivada es el límite de  

h

f(x+h)−f(x)

​

, ya que h va a 0, si ese límite existe.

dθ

d

​

(sin(θ))=(  

h→0

lim

​

 

h

sin(θ+h)−sin(θ)

​

)

Usa la fórmula de suma para el seno.

h→0

lim

​

 

h

sin(h+θ)−sin(θ)

​

 

Simplifica sin(θ).

h→0

lim

​

 

h

sin(θ)(cos(h)−1)+cos(θ)sin(h)

​

 

Reescribe el límite.

(  

h→0

lim

​

sin(θ))(  

h→0

lim

​

 

h

cos(h)−1

​

)+(  

h→0

lim

​

cos(θ))(  

h→0

lim

​

 

h

sin(h)

​

)

Usa el hecho de que θ es una constante al calcular límites, ya que h va a 0.

sin(θ)(  

h→0

lim

​

 

h

cos(h)−1

​

)+cos(θ)(  

h→0

lim

​

 

h

sin(h)

​

)

El límite lim  

θ→0

​

 

θ

sin(θ)

​

 es 1.

sin(θ)(  

h→0

lim

​

 

h

cos(h)−1

​

)+cos(θ)

Para calcular el límite lim  

h→0

​

 

h

cos(h)−1

​

, primero multiplique el numerador y denominador por cos(h)+1.

(  

h→0

lim

​

 

h

cos(h)−1

​

)=(  

h→0

lim

​

 

h(cos(h)+1)

(cos(h)−1)(cos(h)+1)

​

)

Multiplica cos(h)+1 por cos(h)−1.

h→0

lim

​

 

h(cos(h)+1)

(cos(h))  

2

−1

​

 

Usa la identidad pitagórica.

h→0

lim

​

−  

h(cos(h)+1)

(sin(h))  

2

 

​

 

Reescribe el límite.

(  

h→0

lim

​

−  

h

sin(h)

​

)(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)

El límite lim  

θ→0

​

 

θ

sin(θ)

​

 es 1.

−(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)

Usa el hecho de que  

cos(h)+1

sin(h)

​

 es un valor continuo en 0.

(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)=0

Sustituye el valor 0 en la expresión sin(θ)(lim  

h→0

​

 

h

cos(h)−1

​

)+cos(θ).

cos(θ)

5 0
3 years ago
Read 2 more answers
The path of a baseball, hit 3 feet above ground, is modeled by the function f(x)=-0.01x^2+x+3, where f(x) represents the vertica
ozzi

Answer:

Therefore the ball travel 102.92 feet horizontally before hitting the ground

Step-by-step explanation:

Given that, the path of a baseball, hit 3 feet above ground, is modeled by the function

f(x)=-0.01 x^2+x+3

where f(x) represents the vertical height of the ball in feet(Assume) and x is the horizontal distance in feet(Assume) .

When the ball hits the ground, then the vertically distance of the ball will be zero, i.e f(x)=0

\therefore -0.01 x^2+x+3=0

[Applying quadratic formula x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} , here a = -0.001, b=1 and c=3]

\Rightarrow x=\frac{-1\pm\sqrt{1^2-4.(-0.01).3}}{2.(-0.01)}

\Rightarrow x=-2.94, 102.92

Therefore the ball travel 102.92 feet horizontally before hitting the ground.

   

8 0
3 years ago
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