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Nimfa-mama [501]
3 years ago
15

An airport offers two shuttles that run on different schedules. If both shuttles leave the airport at 4:00 p.m., at what time wi

ll they next leave the airport together? Shuttle A leaves every 6min shuttle B leaves every 9 min
Mathematics
2 answers:
mario62 [17]3 years ago
4 0
Basically, we need to find the lowest common multiple of 6 and 9....and that would be 18.

so 18 minutes from 4 p.m. is 4:18 p.m. <===
Kay [80]3 years ago
4 0

Answer:

4:18 P.M.

Step-by-step explanation:

An airport offers two shuttles that run on different schedules.

Shuttle A leaves every 6 minutes shuttle B leaves every 9 minutes.

If both shuttles leave the airport at 4:00 P.M.

We will calculate the time of next leave the airport together.

First we will calculate Lowest Common Multiple (LCM) of 6 and 9.

Factors of 6 = 1 × 2 × 3

Factors of 9 =  1 × 3 × 3

LCM = 1 × 3 × 2 × 3 = 18

Therefore, after 18 minutes to 4:00 P.M. that is 4:18 P.M. they next leave the airport together.

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A rock dropped on the moon will increase its speed from 0 m/s (its starting
belka [17]
<h2>Hello!</h2>

The answer is:

The correct option is the option D

g=1.63\frac{m}{s^{2}}

<h2>Why?</h2>

To calculate the acceleration, we need to use the following formula that involves the given information (initial speed, final speed, and time).

We need to use the following free fall equation:

V_{f}=V_{o}-g*t

Where:

V_{f} is the final speed.

V_{o} is the initial speed.

g is the acceleration due to gravity.

t is the time.

We are given the following information:

V_{f}=8.15\frac{m}{s}

V_{o}=0\frac{m}{s}

t=5seconds

Then, using the formula to isolate the acceleration, we have:

V_{f}=V_{o}-g*t

V_{f}=V_{o}-g*t\\\\g*t=V_{o}-V_{f}\\\\g=\frac{V_{o}-V_{f}}{t}

Now, substituting we have:

g=\frac{V_{o}-V_{f}}{t}

g=\frac{0-8.15\frac{m}{s}}{5seconds}=-1.63\frac{m}{s^{2}}

Therefore, since we are looking for a magnitude, we have that the obtained value will be positive, so:

g=1.63\frac{m}{s^{2}}

Hence, the correct option is the option D

g=1.63\frac{m}{s^{2}}

Have a nice day!

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Answer:

The answer is 14.5

Step-by-step explanation:

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4 years ago
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