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2 years ago

15

Convert 6/9 into a fraction with a denominator of 27.

2 answers:

alex41 [277]2 years ago

6 0

Lets take 6/9. 9 is a multiple of 27, multiply 9 times 3 for a denominator of 27. Whatever we to do the bottom, we do to the top. So multiply 6 by 3 as well for numerator of 18. This gives us our answer, 18/27.

ankoles [38]2 years ago

5 0

Answer: 18/27

Step-by-step explanation: 9 times 3 is 27. To multiply, you have to multiply both the top and the bottom to identify the final answer.

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Kryger [21]

Answer: call him and try to work things out with ur mom as long as both of u are honest

Step-by-step explanation:

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2 years ago

A.70<br> B.40<br> C.140<br> D.20

Nina [5.8K]

The question says that KN bisects JKL. This means that the angles are exactly equal. Thus, we can set the angles equal to each other to solve for x:

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3 years ago

Work out an expression for the nth term for this sequence:<br><br> 23,35,47,49

notsponge [240]

<h3>Answer:</h3>

$a_n = 23 +12(n -1)$

<h3>Explanation:</h3>

The $n$ th term of an arithmetic sequence is explicitly defined as $a_n = a_1 +d(n -1)$ where $a_1$ is the first term of the sequence and $d$ is the the common difference.

From the given first five terms of the sequence we can see that the first term is $23$ so $a_1 = 23$ .

The common difference, $d$ , can be calculated by $a_n - a_{n -1}$ so we'll find the common difference of the given sequence by letting $n = 2$

$d = a_2 - a_{2 -1} \\d = a_2 -a_{1} \\d = 35 -23 \\ d = 12$ .

Now let's plug everything we know.

$a_1 = 23$

$d = 12$

$a_n = 23 + 12(n -1)$

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2 years ago

What is the answer for x? <br><br> 4/9x + 1/5x = 87

marysya [2.9K]

Answer:

13

Step-by-step explanation:

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3 years ago

Read 2 more answers

If U = {x: X € N, 1 < × < 15)

Inessa05 [86]

Answer:

Step-by-step explanation:

Given:

U = {x: X € N, 1 < × < 15) = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}

A = {2,4,6,8,10,12,14}

B = {3,6,9,12,15}

C = {5,10,15}

(a) Verify A(BnB)=(AUB)(AUB)

A U (B n B)

= {2,4,6,8,10,12,14} U ( {3,6,9,12,15} n {3,6,9,12,15} )

= {2,4,6,8,10,12,14} U {3,6,9,12,15}

= {2,3,4,6,8,9,10,12,14,15}

( A U B) n (A U B)

= {2,3,4,6,8,9,10,12,14,15} n {2,3,4,6,8,9,10,12,14,15}

= {2,3,4,6,8,9,10,12,14,15}

Therefore

A U (B n B) = ( A U B) n (A U B)

verifies

(b) Verify An(BUC)=(AnB)u(AnC)

A n ( B U C)

= {2,4,6,8,10,12,14} n ( {3,6,9,12,15} U {5,10,15} )

= {2,4,6,8,10,12,14} n {3,5,6,9,10,12,15}

= {6,10,12}

( A n B ) U ( A n C )

= ( {2,4,6,8,10,12,14} n {3,6,9,12,15} ) U ( {2,4,6,8,10,12,14} n {5,10,15} )

= {6,12} U {10}

= {6,10,12}

Therefore

A n ( B U C) = ( A n B ) U ( A n C )

verifies

(c) Verify AU(BUC)=(AUB)U(AUC)

AU(BUC)

= {2,4,6,8,10,12,14}U{3,6,9,12,15}U{5,10,15}

= {2,3,4,5,6,8,9,10,12,14,15}

(AUB)U(AUC)

= ({2,4,6,8,10,12,14}{3,6,9,12,15})U({2,4,6,8,10,12,14}U{5,10,15})

= {2,3,4,6,8,9,10,12,14,15}U{2,4,5,6,8,10,12,14,15}

= {2,3,4,5,6,8,9,10,12,14,15}

Therefore

AU(BUC)=(AUB)U(AUC)

verifies

5 0

3 years ago