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Semenov [28]
3 years ago
13

Please help, I need to find the area, circumference, and radius

Mathematics
1 answer:
Contact [7]3 years ago
4 0

... What do I do? Please help  Please help, I need to find the area, circumference, and radius

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Can someone help me figure this out no guessing
laiz [17]
Your answer is x = 2.92 = 3.
To answer this question you need to use trigonometry, so the first step is to identify the hypotenuse, opposite, and adjacent.
Because the angle 73 is in the bottom corner next to the length x, we know that the length x is the adjacent. The length 10 is opposite the right angle so this must be the hypotenuse.
We know that cos(θ) = adjacent/hypotenuse, so we can substitute in what we know:
cos(θ) = adjacent/hypotenuse
cos(73) = x/10
Now we can rearrange for x:
cos(73) = x/10
× 10
cos(73) × 10 = x
Finally we just type this into the calculator and get the answer as 2.92 or 3.
I hope this helps!
5 0
3 years ago
Please help these problems are hard​
Pachacha [2.7K]

Answer:

2/5

Step-by-step explanation:

For the denominator you are looking for the total number of options, and in this case it is 10.  Then for the numerator you are looking for what the question is asking for, in this case, it is looking for letters n to q. n, o, p and q are what you are looking for.  With this information you will get 4/10 and simplified, 2/5

6 0
3 years ago
Start at 3. create a pattern that multiplies each number by 3 stop when you have 5 numbers
Gnesinka [82]
3, 6, 9, 12, 15
I did what you asked
7 0
3 years ago
Read 2 more answers
What is the equation of the line ? Please help !!!! First and correct answer will get brainestttt
sergeinik [125]

Answer:

Step-by-step explanation:

Find the slope by doing rise/run

-2/3

Find the y intercept: (0, -2)

The equation will be y = -\frac{2}{3}x - 2

6 0
3 years ago
Is the square root of 225 a rational number?
MArishka [77]

Step-by-step explanation:

\text{The principal square root}:\\\\\sqrt{a}=b\iff a^2=b\ \text{for}\ a\geq0\ \text{and}\ b\geq0.\\\\\text{The square root:}\\\\\sqrt{a}=b\iff b^2=a\ \text{for}\ a\geq0\\===================

\text{If you want the principal square root (arithmetic square root):}\\\\\sqrt{225}=15\ \text{because}\ 15^2=225\\\\\text{If you want square root (algebraic square root):}\\\\\sqrt{225}=\pm15\ \text{because}\ (-15)^2=225\ \text{and}\ 15^2=225

7 0
3 years ago
Read 2 more answers
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