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Zinaida [17]
3 years ago
12

adam walk 2 miles a day for the first week of his exercise plan. the he walk 3 miles a day for the next 9 days. how many miles d

id adam walk in all
Mathematics
1 answer:
Digiron [165]3 years ago
7 0

Answer:

41 miles

Step-by-step explanation:

The first week, which is 7 days, Adam walked 2 miles a day. So, we have the multiplication equation: 2 * 7 = 14 miles.

For the next 9 days, Adam walked 3 miles per day. So, we have the multiplication equation: 3 * 9 = 27 miles.

Now, we just add these two values together:

14 + 27 = 41 miles

Thus, the answer is 41 miles.

Hope this helps!

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4/5 mile in 1/2 hour.

1/2 * 2 = 1

4/5 * 2 = 8/5

8/5 miles per hour or 1.6 miles per hour

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What is greatest common factor of 24, 60, and 36
Mariulka [41]
12 - all divisible by it (2*12=24, 3*12=36, 12*5=60)
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The ball followed a path modelled by the equation h = −0.001! + 0.5 + 2.5 where h is the height of the ball in feet and is the h
Mama L [17]

The heights the balls hit a fence at 350 ft distance are 65 feet, 38 feet and 30 feet, respectively

<h3>Represent the distance-height relationship for each player’s ball as an equation, in a table and on a graph. </h3>

<u>Juan</u>

Juan's equation is given as:

h = -0.001d^2 + 0.5d + 2.5

h =

Set d to multiples of 50 from 0 to 400.

So, the table of values of Juan's function is:

d (ft)                   h(ft)

0                          2.5

50                        25

100                      42.5

150                        55

200                      62.5

250                        65

300                      62.5

350                        65

400                      42.5

See attachment for the graph of Juan's function

<u>Mark</u>

A quadratic function is represented as:

h = ad^2 + bd + c

Using the values on the table of values, we have:

c = 3 -- the constant value

So, the equation becomes

h = ad^2 + bd + 3

Using the two other values on the table of values, we have:

23 = a(50)^2 + b(50) + 3

38 = a(100)^2 + b(100) + 3

Using a graphing tool, we have:

a = -0.001

b = 0.45

So, Mark's equation is h(d) = -0.001d^2 + 0.45d + 3

See attachment for Mark's graph.

<u>Barry</u>

From the graph, we have the table of values of Barry's function to be:

d (ft)                   h(ft)

0                          2.5

50                        21

100                      35

150                       44

200                      48

250                       46

300                      41

350                       30

400                      14

450                      0

Using a graphing tool, we have the quadratic function to be:

y = -0.001x^2 +0.4x +2.5

<h3><u>The shortest and the greatest distance before hitting the ground</u></h3>

From the graphs, equations and tables, the distance travelled by the balls are:

Juan = 505 feet

Mark = 457 feet

Barry = 450 feet

This means that Juan's ball would travel the greatest distance while Barry's ball would travel the shortest.

<h3>The height the balls hit a fence at 350 ft distance</h3>

To do this, we set d = 350

From the graphs, equations and tables, the height at 350 ft by the balls are:

Juan = 65 feet

Mark = 38 feet

Barry = 30 feet

The above represents the height the balls hit the fence

Read more about quadratic functions at:

brainly.com/question/12446886

#SPJ1

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