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MA_775_DIABLO [31]
3 years ago
6

Ralph deposited $3,000 into a bank account that earn simple interest each year after 3.5years he had earn $226.50 and interest i

f no money was deposited into or withdrawn from the account what was the annual interest rate
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
4 0

Answer:

r=0.02147=2.147%

Step-by-step explanation:

Interest=principal X interest rate X time(yearly)

$226.50=$3000 * R * 3.5year

r=0.02147=2.147%

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Step-by-step explanation:

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3 years ago
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What is the answer to 3/x=-3/3x+5
Aleonysh [2.5K]

Answer:

-\frac{5}{4} =x

Step-by-step explanation:

We first need to bring x up into the numerator. I will find common denominators by multiplying both sides by each denominator.

\frac{x(3x+5)}{1} *\frac{3}{x} =\frac{-3}{3x+5}*\frac{x(3x+5)}{1}

This will eliminate both denominators and leave me with

(3x+5)3=-3(x)\\9x+15=-3x after I simplify the parenthesis.

Now I will solve the equation for x by subtracting 9x from both sides.

9x-9x+15=-3x-9x\\15=-12x

Then divide by the coefficient of x.

\frac{15}{-12}=\frac{-12x}{-12}

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7 0
4 years ago
When a man observed a sobriety checkpoint conducted by a police​ department, he saw 671671 drivers were screened and 77 were arr
kifflom [539]

Answer:

P(\overline W)=0.98957

Step-by-step explanation:

Number of drivers Screened = 671

Number Arrested for Driving While Intoxicating = 7

If the W denotes the event of screening a driver and getting someone who is intoxicated.

The Probability of W, P(W)=\frac{7}{671}=0.01043

  • The Probability P(\overline W) is the probability of the event of screening a driver and getting someone who is not intoxicated. Simply put, it is the Probability of the Complement of W.

From Probability Theorem,

P(W)+P(\overline W)=1\\Since \: P(W)=0.01043\\0.01043+P(\overline W)=1\\P(\overline W)=1-0.01043\\=0.98957

8 0
3 years ago
Solve - y = 34. Then graph the solution.
inysia [295]

divide both sides by a negative one to get ride of the -y then on your graph it be a horizontal line at the point (0,-34)

8 0
3 years ago
Suppose (1,19) is on the graph of y = f (x). Which of the following points lies on the graph of the transformed function y = f(1
o-na [289]

Answer:

(5,19) lies on the graph of the transformed function y = f(1/5x)

Step-by-step explanation:

Suppose (1,19) is on the graph of y = f (x)

the graph of the transformed function y = f(1/5x)

y=f(\frac{1}{5}x)

1/5 is multiplied with x  in f(x)

1/5 is less than 1 so there will be a horizontal stretch in the graph by the factor of 1/5

To make horizontal stretch we change the point

f(x)=f(bx) then (x,y) --->( x/b,y)

We divide the x coordinate by the fraction 1/5

(1,19) ----> (\frac{1}{\frac{1}{5}} , 19)= (5,19)

So (5,19) lies on the graph of the transformed function y = f(1/5x)

8 0
3 years ago
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