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MA_775_DIABLO [31]

3 years ago

6

Ralph deposited $3,000 into a bank account that earn simple interest each year after 3.5years he had earn $226.50 and interest i

f no money was deposited into or withdrawn from the account what was the annual interest rate

1 answer:

PilotLPTM [1.2K]3 years ago

4 0

Answer:

r=0.02147=2.147%

Step-by-step explanation:

Interest=principal X interest rate X time(yearly)

$226.50=$3000 * R * 3.5year

r=0.02147=2.147%

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Wesley wants to have at least $50 to spend each day of his 7-day vacation. He plans to save $30 each month for 12 months. Which

aleksklad [387]

Answer:

i cant choose any that applies to this question because there is no picture added to it and there are no choices to choose from. If i were to solve it though, it would be; yes, he will save enough money for his vacation.

Step-by-step explanation:

I know he would have enough--and in this case more than enough, because since he's planning to save $30 for a whole year just for $50, when he could simply make $60--which is in fact more than needed for his goal-- in just 2 months. If he were to stick with his plan though, he'd make $360. I got that by multiplying 30 by 12.

3 0

2 years ago

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Taya2010 [7]

Answer:

7.3≤x<7.4

Step-by-step explanation:

6 0

2 years ago

Choose the proper steps needed to solve the following equation and give the

trasher [3.6K]

Combine like terms, then divide by 7

4 0

2 years ago

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Find the linear approximation of the function f(x, y, z) = x2 + y2 + z2 at (6, 3, 2) and use it to approximate the number 6.022

lisov135 [29]

Answer:

$f(6.022,2.922,1.972)\approx 49.10400$

Step-by-step explanation:

The partial derivatives fo the function are:

$\frac{\partial f}{\partial x} = 2\cdot x$

$\frac{\partial f}{\partial y} = 2\cdot y$

$\frac{\partial f}{\partial z} = 2\cdot z$

The linear approximation of the function at given value is:

$f(6.022,2.992,1.972) \approx f(6,3,2) + \frac{\partial f(6,3,2)}{\partial x}\cdot (6.022-6) + \frac{\partial f(6,3,2)}{\partial y}\cdot (2.992-3) + \frac{\partial f(6,3,2)}{\partial z}\cdot (1.972-2)$

$f(6.022,2.922,1.972)\approx 49 + 12\cdot (6.022 - 6) + 6 \cdot (2.992-3)+ 4 \cdot (1.972-2)$

$f(6.022,2.922,1.972)\approx 49.10400$

3 0

2 years ago

Write an equation of a parabola in vertex form. Vertex (2,-3) and passes through (0,5)

Strike441 [17]

The parabola equation in vertex form passes through (0,5) is $y=2(x-2)^{2}-3$

<u>Solution:</u>

Given that, vertex of a parabola is (2,-3) and the parabola passes through the point (0, 5)

We have to find the equation of parabola in vertex form.

<em><u>The general form of parabola equation in vertex form is given as:</u></em>

$y=a(x-h)^{2}+k$

Where (h, k ) is vertex and "a" is a constant

Here in our problem, h = 2 and k = - 3

By substituting the values in general form we get,

$\begin{array}{l}{y=a(x-2)^{2}+(-3)} \\\\ {\rightarrow y=a(x-2)^{2}-3}\end{array}$

Now, we know that it passes through (0, 5). So substitute x = 0 and y = 5

$\begin{array}{l}{\rightarrow 5=a(0-2)^{2}-3} \\\\ {\rightarrow a(-2)^{2}=5+3} \\\\ {\rightarrow 4 a=8} \\\\ {\rightarrow a=2}\end{array}$

So substituting the value of "a" we get,

$y=2(x-2)^{2}-3$

Hence, the parabola equation in vertex form is $y=2(x-2)^{2}-3$

5 0

3 years ago