Assume that pi is approx. 3.14. Then 86.92 = approx. 27 2/3 times pi, or
86.92 is approx. equal to 83pi/3.
Answer:
∠D
∠EDC
∠CDE
Step-by-step explanation:
those are the only ways I can think of, I hope that helps :)
![1\text{ and }\frac{\text{-1 }}{2}\pm\text{ }\frac{i\sqrt[]{3^{}}}{2}\text{ (option C)}](https://tex.z-dn.net/?f=1%5Ctext%7B%20and%20%7D%5Cfrac%7B%5Ctext%7B-1%20%7D%7D%7B2%7D%5Cpm%5Ctext%7B%20%7D%5Cfrac%7Bi%5Csqrt%5B%5D%7B3%5E%7B%7D%7D%7D%7B2%7D%5Ctext%7B%20%28option%20C%29%7D)
Explanation:
![\begin{gathered} x^3-\text{ 1 = 0} \\ x^3-\text{ 1 has a root of 1} \\ x^3-1=(x-1)(x^2\text{ + x + 1)} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5E3-%5Ctext%7B%201%20%3D%200%7D%20%5C%5C%20x%5E3-%5Ctext%7B%201%20has%20a%20root%20of%201%7D%20%5C%5C%20x%5E3-1%3D%28x-1%29%28x%5E2%5Ctext%7B%20%2B%20x%20%2B%201%29%7D%20%5Cend%7Bgathered%7D)
we find the root of x² + x + 1 has it can't be factorized
Using quadratic formula:
![x\text{ = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%5Ctext%7B%20%3D%20%7D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
for a² + bx + c = 0
comparing: x² + x + 1
where a = 1, b = 1, c = 1
![\begin{gathered} x\text{ = }\frac{-1\pm\sqrt[]{(1)^2^{}-4(1)(1)}}{2(1)} \\ x\text{ = }\frac{-1\pm\sqrt[]{1^{}-4}}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5Ctext%7B%20%3D%20%7D%5Cfrac%7B-1%5Cpm%5Csqrt%5B%5D%7B%281%29%5E2%5E%7B%7D-4%281%29%281%29%7D%7D%7B2%281%29%7D%20%5C%5C%20x%5Ctext%7B%20%3D%20%7D%5Cfrac%7B-1%5Cpm%5Csqrt%5B%5D%7B1%5E%7B%7D-4%7D%7D%7B2%7D%20%5Cend%7Bgathered%7D)
![\begin{gathered} x\text{ = }\frac{-1\pm\sqrt[]{-3}}{2}\text{= }\frac{-1\pm\sqrt[]{-1(3)}}{2} \\ Since\text{ we can't find the square root of a negative number, we apply complex root} \\ \text{let i}^2\text{ = -1} \\ x\text{ = }\frac{-1\pm\sqrt[]{3i^2}}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5Ctext%7B%20%3D%20%7D%5Cfrac%7B-1%5Cpm%5Csqrt%5B%5D%7B-3%7D%7D%7B2%7D%5Ctext%7B%3D%20%7D%5Cfrac%7B-1%5Cpm%5Csqrt%5B%5D%7B-1%283%29%7D%7D%7B2%7D%20%5C%5C%20Since%5Ctext%7B%20we%20can%27t%20find%20the%20square%20root%20of%20a%20negative%20number%2C%20we%20apply%20complex%20root%7D%20%5C%5C%20%5Ctext%7Blet%20i%7D%5E2%5Ctext%7B%20%3D%20-1%7D%20%5C%5C%20x%5Ctext%7B%20%3D%20%7D%5Cfrac%7B-1%5Cpm%5Csqrt%5B%5D%7B3i%5E2%7D%7D%7B2%7D%20%5Cend%7Bgathered%7D)
![\begin{gathered} x\text{ = }\frac{-1\pm\sqrt[]{3i^2}}{2}\text{ = }\frac{-1\pm i\sqrt[]{3^{}}}{2} \\ x\text{ = }\frac{-1+i\sqrt[]{3^{}}}{2}or\text{ }\frac{-1-i\sqrt[]{3^{}}}{2} \\ \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%5Ctext%7B%20%3D%20%7D%5Cfrac%7B-1%5Cpm%5Csqrt%5B%5D%7B3i%5E2%7D%7D%7B2%7D%5Ctext%7B%20%3D%20%7D%5Cfrac%7B-1%5Cpm%20i%5Csqrt%5B%5D%7B3%5E%7B%7D%7D%7D%7B2%7D%20%5C%5C%20x%5Ctext%7B%20%3D%20%7D%5Cfrac%7B-1%2Bi%5Csqrt%5B%5D%7B3%5E%7B%7D%7D%7D%7B2%7Dor%5Ctext%7B%20%7D%5Cfrac%7B-1-i%5Csqrt%5B%5D%7B3%5E%7B%7D%7D%7D%7B2%7D%20%5C%5C%20%20%5Cend%7Bgathered%7D)
Answer:
130
Step-by-step explanation:
Answer:
Option B 3412
Step-by-step explanation:
we know that
step 1
75°+x=90° -----> by complementary angles
step 2
Solve for x
Subtract 75 both sides
75°-75°+x=90°-75°
step 3
x=15°
step 4
Verify
Substitute the value of x in the equation of the step 1
75°+15°=90°
90°=90° ----> is correct
therefore
The correct order is
3-4-1-2