1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Scilla [17]
3 years ago
9

Activity

Mathematics
2 answers:
Simora [160]3 years ago
5 0

Answer:

part A : Angles A, B, and C form a triangle. The sum of the angle measurements of a triangle is 180°. So, I can find the measurement of angle C by subtracting the measurements of angle A and angle B from 180°.

part B: Angle A and angle B each measure 25°. Find the measurement of angle C by subtracting the measurements of angle A and angle B from 180°. The numerical expression for the measurement of angle C is 180° – 25° – 25°.

part C: The measurement of angle C is given by the expression 180° – 25° – 25°. So, angle C measures 130°.

part D:Angle L and angle C are supplementary angles. The sum of supplementary angles is 180°. So, I can find the measurement of angle L by subtracting the measurement of angle C from 180°.

part E: Angle C measures 130°. Find the measure of angle L by subtracting the measurement of angle C from 180°. The numerical expression for the measure of angle L is 180° – 130°.

part F: The measurement of angle L is given by the expression 180° – 130°. So, angle L measures 50°.

Step-by-step explanation:

these are all 100% correct and they are the exact anwsers on the edmentum.

Gelneren [198K]3 years ago
3 0

Answer:

Okay, so because angles A, B, and C make a triangle and a triangle is 180 degrees. So, because we know both A and B's measurement's, we can figure out the measurement of C. We can find the measurement of angle C by adding angles A and B and subtracting the total by 180 degrees.

Step-by-step explanation:

You might be interested in
Which functions domain consists of only real numbers greater than 3
Maru [420]
Can't take the square root of a negative so find a domain where it takes squaer root of 0 wich is allowed hold a sec

f(x)= \frac{2}{ \sqrt{x-3} }
there
the denomenator can't be 0 so x cannot be 3, it has to be greater
6 0
3 years ago
What is the formula of simple interest?​
Annette [7]

Answer:

simple interest = principle*rate*time

5 0
4 years ago
Read 2 more answers
ANSWER THIS PLS!!!!
astra-53 [7]

Answer and Step-by-step explanation: With the constant velocity motion formula, we can determine constant velocity of the object in motion whose data we collected:

x = x₀ + vt

Velocity can be calculated as:

v=\frac{x-x_{0}}{t}

v=\frac{70-40}{10}

v = 3 m/s

The beginning of the data collect, object is 40m away, then x₀ = 40.

So, equation modeling the object's path is x = 40 + 3t.

5 0
3 years ago
What is 8.57 as a fraction or a mixed number
AURORKA [14]
8\frac{57}{100} or \frac{857}{100}
7 0
4 years ago
Read 2 more answers
Is the mean <br> always in the data values
Tju [1.3M]
It might just be old pal :)
4 0
3 years ago
Other questions:
  • Angles opposite to one another at the intersection of two lines are called ____ angles.
    6·2 answers
  • A baseball is thrown into the air with an upward velocity of 30ft/s. Its height h, in feet, after t seconds is given by the func
    8·1 answer
  • Choose the correct slope of the line that passes through the points (-4, 8) and (-3, -6).. Answer. 0. 14. 7. -14.
    14·2 answers
  • What is this expression in simplified form? <br>​
    14·1 answer
  • 1.44 equals how many hundrethds
    12·1 answer
  • What is the word for “to find a approximate value for a number”?
    5·1 answer
  • 3/4 + (1/3 ÷ 1/6) - (-1/2)<br> Please give answer as a fraction
    13·2 answers
  • What is the sum of the interior angles of the polygon?
    5·2 answers
  • pls answer this Explain when you would use miles versus when you would use inches to reference a length measurement.
    8·1 answer
  • 1/3 (4+18) -2 to the 2nd power
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!