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tatyana61 [14]
2 years ago
9

The nose of the origami dog is a right angle with sides that are 2 cm, 3 cm, and 3.6 cm long. What is the area of this triangle?

Mathematics
1 answer:
Maslowich2 years ago
4 0

Given:

The sides of a right triangle are 2 cm, 3 cm, and 3.6 cm.

To find:

The area of the right triangle.

Solution:

Area of a triangle is:

Area=\dfrac{1}{2}\times base\times height

In the given triangle 3.6 cm is the largest side, it means 3.6 cm is the length of the hypotenuse. So, 2 cm and 3 cm and the base and height of the triangle.

Now, the area of the given triangle is:

Area=\dfrac{1}{2}\times 2\times 3

Area=3

Therefore, the area of the given triangle is 3 square cm.

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Write the equation of the line that passes through (5.-9) and (2.5).
Kipish [7]

Answer:

y = -14/3x + 43/3

Step-by-step explanation:

y2 - y1 / x2 - x1

5 - (-9) / 2 - 5

14 / -3

- 14/3

y = -14/3x + b

5 = -14/3(2) + b

5 = -28/3 + b

43/3 = b

y = -14/3x + 43/3

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X + 3 = y <br><br> solve for x
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Subtract 3 from each side to isolate the x and you get x=y-3
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The ratio of the width of the rectangle to the height of the rectangle is ?
Karo-lina-s [1.5K]
The area of a rectangle is 108cm (squared. the ratio of the width to the length is 3:4
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3 years ago
A total of $5000 is invested: part at 7% and the remainder at 12%. How much is invested at each rate if the annual interest is $
atroni [7]

The amount invested in the account that yields 7% interest is $4000.

The amount invested in the account that yields 12% interest is $1000.

<h3>What are the linear equations that represent the question?</h3>

a + b = 5000 equation 1

0.07a + 0.12b = 400 equation 2

Where:

a = amount invested in the account that yields 7% interest.

b =  amount invested in the account that yields 12% interest.

<h3>How much is invested at each rate?</h3>

Multiply equation 1 by 0.07

0.07a + 0.07b = 350 equation 3

Subtract equation 3 from equation 2

0.05b = 50

b = 50 / 0.05

b = 1000

Subtract 1000 from 5000: 5000 - 1000 = 4000

To learn more about linear functions, please check: brainly.com/question/26434260

#SPJ1

3 0
2 years ago
To prove :One plus cot square theta into tan theta by sec square theta = cot theta
pickupchik [31]

we are given

\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)

We will simplify left side and make it equal to right side

Left side:

\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)}

we can use trigonometric identity

1+cot^2(\theta)=csc^2(\theta)

we can replace it

\frac{(csc^2(\theta))*tan(\theta)}{sec^2(\theta)}

we know that

csc=1/sin and sec=1/cos

so, we can replace it

and we get

\frac{cos^2(\theta)tan(\theta)}{sin^2(\theta)}

now, we know that

tan =sin/cos

\frac{cos^2(\theta)*sin(\theta)}{sin^2(\theta)*cos(\theta)}

we can simplify it

and we get

\frac{cos(\theta)}{sin(\theta)}

we can also write it as

=cot(\theta)

Right Side:

cot(\theta)

we can see that

left side = right side

so,

\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)......Answer

6 0
3 years ago
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