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uranmaximum [27]
2 years ago
6

The identification of the technology management framework contain?

Computers and Technology
1 answer:
AlexFokin [52]2 years ago
8 0

Answer:

Explanation:

The effective management of technology as a source of competitive advantage is of vital importance for many organizations. It is necessary to understand, communicate and integrate technology strategy with marketing, financial, operations and human resource strategies. This is of particular importance when one considers the increasing cost, pace and complexity of technology developments, combined with shortening product life cycles. A five process model provides a framework within which technology management activities can be understood: identification, selection, acquisition, exploitation and protection. Based on this model, a technology management assessment procedure has been developed, using an ``action research’’ approach. This paper presents an industrial case study describing the first full application of the procedure within a high-volume manufacturing business. The impact of applying the procedure is assessed in terms of benefits to the participating business, together with improvements to the assessment procedure itself, in the context of the action research framework. Keyword: Technology, Strategy, Management, Assessment

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Answer:

a) The volume of oxygen used for combustion at STP is approximately 305 dm³

b) The volume of gas released during combustion at STP is approximately 508 dm³

Explanation:

The given chemical reaction equation for the burning of ethanol in air, is presented as follows;

2CH₃CH₂OH (l) + 6O₂ (g) → 4CO₂ (g) + 6H₂O

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The molar mass of ethanol, MM = 46.06844 g/mol∴

The number of moles of ethanol in the reaction, n = m/MM

∴ n = 209 g/(46.06844 g/mol) ≈ 4.537 moles

a) Given that 2 moles of ethanol, CH₃CH₂OH reacts with 6 moles of oxygen gas molecules, O₂, 4.54 moles of ethanol will react with (6/2) × 4.537 = 13.611  moles of oxygen

The volume occupied by one mole os gas at STP = 22.4 dm³

The volume occupied by the 13.611 moles of oxygen gas at STP, 'V', is given as follows;

V = 13.611 mol × 22.4 dm³/mole = 304.8864 dm³ ≈ 305 dm³

The volume occupied by the 13.611 moles of oxygen gas at STP, V = The volume of oxygen used for the combustion ≈ 305 dm³

b) The total number of moles of gases released in the reaction, is given as follows;

The total number of moles = (4.537/2) × (4 + 6) = 22.685 moles of gas

The total volume of gas released, V_T = The volume of gas released during the combustion at STP = 22.685 moles × 22.4 dm³/mole = 508.144 dm³ ≈ 508 dm³

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