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Ivanshal [37]
3 years ago
9

Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.5 parts

/million (ppm). A researcher believes that the current ozone level is not at a normal level. The mean of 24 samples is 7.8 ppm with a standard deviation of 0.7. Assume the population is normally distributed. A level of significance of 0.02 will be used. Find the value of the test statistic. Round your answer to three decimal places.
Mathematics
1 answer:
Hunter-Best [27]3 years ago
7 0

Answer:

The value of the test statistic is t = 2.1

Step-by-step explanation:

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the expected value, \sigma is the standard deviation and n is the size of the sample.

The level of ozone normally found is 7.5 parts/million (ppm).

This means that \mu = 7.5

The mean of 24 samples is 7.8 ppm with a standard deviation of 0.7.

This means that X = 7.8, \sigma = 0.7, n = 24

Test Statistic:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{7.8 - 7.5}{\frac{0.7}{\sqrt{24}}}

t = 2.1

The value of the test statistic is t = 2.1

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For the second function:

\begin{gathered} y=2x^2 \\ \Rightarrow x=-2: \\ y=2(-2)^2=2*4 \\ y=8 \\ \Rightarrow x=0: \\ y=2(0)^2=2*0 \\ y=0 \\ \Rightarrow x=2: \\ y=2(2)^2=2*4 \\ y=8 \end{gathered}

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