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Darya [45]
3 years ago
15

Write an equation perpendicular to y = -2x - 7 that passes through the point (4,6)

Mathematics
2 answers:
pshichka [43]3 years ago
8 0
THE ANSWER IS: y=1/2x+4

to find a perpendicular line, get the reciprocal of the slope and multiply by -1
so since the given slope is -2, the reciprocal is -1/2 and multiply by -1 to get 1/2

then put the new slope and the given point into point slope form of a linear equation which is: (y-y1)=m(x-x1)
m=slope= 1/2
given point (x1,y1) = (4,6)
(y-6)=1/2(x-4)

you can multiply this out or get standard form:
y-6=1/2x-2
y=1/2+4
blagie [28]3 years ago
6 0
There is no photo of the equation I can’t help you if you don’t give me something to work with
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seropon [69]

<em>Greetings from Brasil</em>

From radiciation properties:

\large{A^{\frac{P}{Q}}=\sqrt[Q]{A^P}}

bringing to our problem

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4 years ago
Someone please help me on this!
Alexxx [7]

Answer & Step-by-step explanation:

This can be proven with the SAS theorem (side-angle-side)

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GJ=IJ

and it creates two 90° angles:

∠GJH=∠IJH

And because of the reflexive property of congruence:

JH=JH

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:Done

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3 years ago
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katrin [286]

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15.3125

Step-by-step explanation:

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