<h3>
<u>Answer:</u></h3>

<h3>
<u>Step-by-step explanation:</u></h3>
A inequality is given to us and we need to convert it into standard form and see whether if it has a solution . So let's solve the inequality.
The inequality given to us is :-

Let's plot a graph to see its interval . Graph attached in attachment .
Now we can see that the Interval notation of would be ,
![\boxed{\boxed{\orange \tt \purple{\leadsto}y \in [-2,-1] }}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cboxed%7B%5Corange%20%5Ctt%20%5Cpurple%7B%5Cleadsto%7Dy%20%5Cin%20%5B-2%2C-1%5D%20%7D%7D)
<h3>
<u>Hence</u><u> the</u><u> </u><u>standa</u><u>rd</u><u> </u><u>form</u><u> </u><u>of</u><u> </u><u>inequa</u><u>lity</u><u> </u><u>is</u><u> </u><u>y²</u><u>+</u><u>3y</u><u> </u><u>+</u><u>2</u><u> </u><u>≤</u><u> </u><u>0</u><u> </u><u>and</u><u> </u><u>the </u><u>Solution</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ineq</u><u>uality</u><u> </u><u>is</u><u> </u><u>[</u><u> </u><u>-</u><u>2</u><u> </u><u>,</u><u> </u><u>-</u><u>1</u><u> </u><u>]</u><u> </u><u>.</u></h3>
Answer:
Tristan is correct, because he needs to find the possible dimensions for rectangle WXYZ and then divide each dimension by 3.
Step-by-step explanation:
The rectangle ABCD is dilated by a factor of 3 to get the rectangle WXYZ whose area is found to be 72 cm².
Let the dimensions of the dilated rectangle WXYZ are a cm by b cm.
So, ab = 72 ........... (1)
Now, the dimensions of the original rectangle are 3 times lesser than the dimensions of rectangle WXYZ.
So, the area of rectangle ABCD will be
cm² {from equation (1)}
Therefore, Tristan is correct, because he needs to find the possible dimensions for rectangle WXYZ and then divide each dimension by 3. (Answer)
Answer:
the sqaure root of 1 is 1
Step-by-step explanation:
<span>What is 4 divided by 84?
4 </span>÷ 84 = <span>0.04761904761....
4 divided by 84 isn't 21, but 84 divided by 4 is 21! 4 divided by 84 is asking how many times 84 goes into 4 which is not even 1.
</span>
4 divided by 84 = <span>0.04761904761....</span>