Answer:
D
Step-by-step explanation:
You put square roots of 148 in the calculator than it will give you the answer
A quadratic always has two solutions. They could be two real number solutions (the parabola crosses the x-axis in two places), one real number double solution (the parabola just touches the x-axis in one spot) to two complex (imaginary) solutions where the parabola doesn't cross the x-axis.
Please give me brainliest
Hello from MrBillDoesMath!
Answer:
See Discussion below
Discussion:
(sinq + cosq)^2 = => (a +b)^2 = a^2 + 2ab + b^2
(sinq)^2 + (cosq)^2 + 2 sinq* cosq => as (sinx)^2 + (cosx)^2 = 1
1 + 2 sinq*cosq (*)
Setting a = b = q in the trig identity:
sin(a+b) = sina*cosb + cosa*sinb
sin(2q) = (**)
sinq*cosq + cosq*sinq => as both terms are identical
2 sinq*cosq
Combining (*) and (**)
(sinq + cosq)^2 = 1 + 2sinq*cosq => (**) 2sinq*cosq = sqin(2q)
= 1 + sin(2q)
Hence
(sinq + cosq)^2 = 1 + sin(2q) => subtracting 1 from both sides
(sinq + cosq)^2 - 1 = sin(2q)
The last statement is what we are trying to prove.
Thank you,
MrB
Answer:
A and C
Step-by-step explanation:
The absolute value of a negative number is positive; I don't know why A and C are identical though
The solution set of 3x+5=x+2 is x=-1. This is because you want to get the variables on one side and the numbers on the other. you subtract x on both sides and subtract 5 on both sides. your equation then becomes 3x=-3. you then divide 3 on both sides and you get your answer of x=-1.
