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2 years ago

The larger of two consecutive integers is 10 more than 4 times the smaller. Find the integers.

Mathematics

1 answer:

nevsk [136]2 years ago

3 0

Answer:

-2 and -3

Step-by-step explanation:

Let L represent the large integer and S represent the smaller integer

Given Large Integer = 10 + 4 times Smaller Integer

Mathematically:

L = 10 + 4S -------eq 1

It is also given that the integers are consecutive,

hence L = S + 1------ eq2

Now we can solve a system of equations by substitution.

Substitute eq 2 into eq 1

S + 1 = 10 + 4S (subtract 1 from both sides)

S = 10 - 1 + 4S

S = 9 + 4S (subtract 4S from both sides)

S - 4S = 9

-3S = 9 (divide both sides by -3)

S = 9 / (-3) = -3 (answer)

form equation 2,

L = S + 1

L = -3 + 1

L = -2 (answer)

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Therefore, the correct option is a.Quadrilateral DEFG is a rhombus because opposite sides are parallel and all four sides have the same length.

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