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2 years ago

The larger of two consecutive integers is 10 more than 4 times the smaller. Find the integers.

Mathematics

1 answer:

nevsk [136]2 years ago

3 0

Answer:

-2 and -3

Step-by-step explanation:

Let L represent the large integer and S represent the smaller integer

Given Large Integer = 10 + 4 times Smaller Integer

Mathematically:

L = 10 + 4S -------eq 1

It is also given that the integers are consecutive,

hence L = S + 1------ eq2

Now we can solve a system of equations by substitution.

Substitute eq 2 into eq 1

S + 1 = 10 + 4S (subtract 1 from both sides)

S = 10 - 1 + 4S

S = 9 + 4S (subtract 4S from both sides)

S - 4S = 9

-3S = 9 (divide both sides by -3)

S = 9 / (-3) = -3 (answer)

form equation 2,

L = S + 1

L = -3 + 1

L = -2 (answer)

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A rubber ball has a radius of about 2.86 in. Can the ball be packaged in a box shaped like a cube with a volume of 125 in3?

Vlada [557]

Answer:

I am not sure what the values needed to add in / etc, but here is the height of the box: 5

Step-by-step explanation:

A cube is a kind of rectangle where all the sides are the same. So to find volume, cube the length of any side. To find height, calculate the cube root of a cube's volume. For this example, the cube has a volume of 125. The cube root of 125 is 5. The height of the cube is 5.

(hopefully this is correct, have a nice day!)

6 0

2 years ago

Determine all prime numbers a, b and c for which the expression a ^ 2 + b ^ 2 + c ^ 2 - 1 is a perfect square .

kogti [31]

Answer:

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Step-by-step explanation:

From Algebra we know that a second order polynomial is a perfect square if and only if $(x+y)^{2} = x^{2} + 2\cdot x\cdot y + y^{2}$ . From statement, we must fulfill the following identity:

$a^{2} + b^{2} + c^{2} - 1 = x^{2} + 2\cdot x\cdot y + y^{2}$

By Associative and Commutative properties, we can reorganize the expression as follows:

$a^{2} + (b^{2}-1) + c^{2} = x^{2} + 2\cdot x \cdot y + y^{2}$ (1)

Then, we have the following system of equations:

$x = a$ (2)

$(b^{2}-1) = 2\cdot x\cdot y$ (3)

$y = c$ (4)

By (2) and (4) in (3), we have the following expression:

$(b^{2} - 1) = 2\cdot a \cdot c$

$b^{2} = 1 + 2\cdot a \cdot c$

$b = \sqrt{1 + 2\cdot a\cdot c}$

From Number Theory, we remember that a number is prime if and only if is divisible both by 1 and by itself. Then, $a, b, c > 1$ . If $a$ , $b$ and $c$ are prime numbers, then $2\cdot a\cdot c$ must be an even composite number, which means that $a$ and $c$ can be either both odd numbers or a even number and a odd number. In the family of prime numbers, the only even number is 2.

In addition, $b$ must be a natural number, which means that:

$1 + 2\cdot a\cdot c \ge 4$

$2\cdot a \cdot c \ge 3$

$a\cdot c \ge \frac{3}{2}$

But the lowest possible product made by two prime numbers is $2^{2} = 4$ . Hence, $a\cdot c \ge 4$ .

The family of all prime numbers such that $a^{2} + b^{2} + c^{2} -1$ is a perfect square is represented by the following solution:

$a$ is an arbitrary prime number. (1)

$b = \sqrt{1 + 2\cdot a \cdot c}$ (2)

$c$ is another arbitrary prime number. (3)

Example: $a = 2$ , $c = 2$

$b = \sqrt{1 + 2\cdot (2)\cdot (2)}$

$b = 3$

4 0

2 years ago

two sides of a triangle measures 25 cm + 35 CM which of the following would be the measure of the third side

Oxana [17]

Assuming those are the legs of the triangle and that you need to find the hypotenuse... I would use the formula: a^2+b^2=c^2
It doesn't matter what a and b are, just fill it in.
25^2+35^2=c^2
625+1225=c^2
1850=c^2
Take the square root of 1850, it isn't a perfect square so I got: 43.01.
If you want, just round it to 43, idc.
So, if I were to check my work, I would need to remember that the hypotenuse is the longest side.
Since 43 is the hypotenuse, it is the longest side.

5 0

3 years ago

The answer to 4(7m+6f)

Mekhanik [1.2K]

Answer:

28m + 24f

Step-by-step explanation:

4(7m + 6f)

28m + 24f (distributive property of equality)

8 0

2 years ago

Is the ordered pair (-2, 1) a solution to the equation - 3x + y = 5? <br>No <br>Yes

Otrada [13]

Answer:

Step-by-step explanation:

Plug (-2,1) into -3x+y=5. This will make it -3(-2)+(1)=5. This is equal to 6+1=5. 7=5. 7 is not equal to 5. Therefore, (-2,1) is not a solution to the equation -3x+y=5.

If this helps please mark as brainliest

6 0

2 years ago