Simplify answer is 6x + 21
check the picture below.
if ∡F = 90° and ∡D = 30°, then the ∡A = 60°, meaning the triangle is a 30-60-90 triangle and therefore we can use the 30-60-90 rule as you see in the picture.
![\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ h=7\sqrt{3}\\ b=7 \end{cases}\implies A=\cfrac{1}{2}(7)(7\sqrt{3}) \\\\\\ A=\cfrac{49\sqrt{3}}{2}\implies A\approx 42.43524478543749369142](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20triangle%7D%5C%5C%5C%5C%0AA%3D%5Ccfrac%7B1%7D%7B2%7Dbh~~%0A%5Cbegin%7Bcases%7D%0Ab%3Dbase%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Ah%3D7%5Csqrt%7B3%7D%5C%5C%0Ab%3D7%0A%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%287%29%287%5Csqrt%7B3%7D%29%0A%5C%5C%5C%5C%5C%5C%0AA%3D%5Ccfrac%7B49%5Csqrt%7B3%7D%7D%7B2%7D%5Cimplies%20A%5Capprox%2042.43524478543749369142)
Answer:
603.2 meters
Step-by-step explanation:
circle - the outside of the walk in this case. This circle has a
diameter of 22 + 8 m, therefore a radius of 15m. The inner circle
has a diameter of 22m - as given - a radius of 11m.
You subtract the area of the inner circle from that of the larger circle.
The sketch of the garden and the pond is shown below
Area of garden = length × width
Area of garden = [3x + 5] × 3x
Area of garden = 3x[3x+5]
Area of garden = 9x² + 15x
Area of pond = [x-2] × x
Area of pond = x[x-2]
Area of pond = x² - 2x
Area to be re-sod = Area of garden - Area of pond
Area to be re-sod = 9x² + 15x - [x² - 2x]
Area to be re-sod = 9x² - x² + 15x + 2x
Area to be re-sod = 8x² + 17x
The amount of sod needed to be bought would depend on how much in each packaging they are being sold.