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2 years ago

Anybody know the answer

Mathematics

2 answers:

Ann [662]2 years ago

7 0

Answer:

5(9 - x)

Step-by-step explanation:

The product of 2 numbers, is just multiplication

But in this expression, we are multiplying a number by the difference of two other numbers, hence why we should group 9 - x in parentheses.

Karolina [17]2 years ago

4 0

Answer:

5 (-9x)

Step-by-step explanation:

Product of 5

5 * ()

difference of 9

5 * (-9)

and a number

5 * (-9x)

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What is the power of ten in (8.91 x 10^2) (3.3 x 10^12)?

NNADVOKAT [17]

In this problem, the power of 10 is 14. Hope this helps!

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3 years ago

Find the inverse of the given matrix, if it exists.Aequals=left bracket Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column 0 3

BabaBlast [244]

Answer:

$A^{-1}=\left[ \begin{array}{ccc} \frac{1}{9} & \frac{4}{27} & - \frac{2}{27} \\\\ \frac{8}{9} & \frac{5}{27} & \frac{11}{27} \\\\ - \frac{4}{9} & \frac{2}{27} & - \frac{1}{27} \end{array} \right]$

Step-by-step explanation:

We want to find the inverse of $A=\left[ \begin{array}{ccc} 1 & 0 & -2 \\\\ 4 & 1 & 3 \\\\ -4 & 2 & 3 \end{array} \right]$

To find the inverse matrix, augment it with the identity matrix and perform row operations trying to make the identity matrix to the left. Then to the right will be inverse matrix.

So, augment the matrix with identity matrix:

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 4&1&3&0&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Subtract row 1 multiplied by 4 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ -4&2&3&0&0&1\end{array}\right]$

Add row 1 multiplied by 4 to row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&2&-5&4&0&1\end{array}\right]$

Subtract row 2 multiplied by 2 from row 3

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&-27&12&-2&1\end{array}\right]$

Divide row 3 by −27

$\left[ \begin{array}{ccc|ccc}1&0&-2&1&0&0 \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Add row 3 multiplied by 2 to row 1

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&11&-4&1&0 \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

Subtract row 3 multiplied by 11 from row 2

$\left[ \begin{array}{ccc|ccc}1&0&0&\frac{1}{9}&\frac{4}{27}&- \frac{2}{27} \\\\ 0&1&0&\frac{8}{9}&\frac{5}{27}&\frac{11}{27} \\\\ 0&0&1&- \frac{4}{9}&\frac{2}{27}&- \frac{1}{27}\end{array}\right]$

As can be seen, we have obtained the identity matrix to the left. So, we are done.

6 0

2 years ago

I don’t know how to do this question pls help

sineoko [7]

Answer:

Step-by-step explanation:

Triangle P is mapped onto Q so P is the initial triangle that will transformed.

We can rotate counterclockwise 90° but we cannot do it about the origin (0,0) because the red point (5, 1) will end up at ( -1, 5) .

We see that the point (5, 1) ends up at ( -2, 4) so the center of rotation is lower than the origin.

The transformation is rotation of 90° about the point (0,-1)

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2 years ago

Solve the inequality <br> 42 < -6d

sergiy2304 [10]

-6d > 42
d < 42 / (-6)
d < -7

8 0

3 years ago

. A tennis supply store pays a wholesaler $90 for a tennis racquet and sells it for $144. What is the markup rate?

I am Lyosha [343]

Formula : Amount of change / Original amount

1. 144 - 90/ 144

2. Subtract 144 and 90

3. 54/ 144

4. Divide 54 by 144

5 0.375

6 Move the decimal two places to the right.

7. 37.5 %

Answer: 37.5% is the markup rate

6 0

3 years ago