Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
13 x^2 -6x -9
Step-by-step explanation:
8x^2-4x-3+5x^2-2x-6
Combine like terms
8x^2+5x^2 -4x-2x -6-3
13 x^2 -6x -9
The answer would be D - 1/6
This is because there are six sides to the die and just because he rolled all 3s before it does not mean he has a better chance to roll a 3 now.
Since there is only 1 3 on the six sided die there is a 1/6 chance he would roll a 3.
Step-by-step explanation:
hope this helps you
thanks
