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Scorpion4ik [409]
2 years ago
13

Use any method you like to find the measure of angle A

Mathematics
1 answer:
lutik1710 [3]2 years ago
4 0
A = 71.5 degrees (1 dp)

cos(A) = (21^2 + 16^2 - 22^2) / (2 x 21 x 16)
= 0.31696...
A = cos^-1(0.31696...) = 71.5 degrees
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A rhombus has four 6-inch sides and two 120-degree angles. From one of the vertices of the obtuse angles, the two latitudes are
nikitadnepr [17]

Answer:

Area(A)=Area(C)= 9 in^{2}

Area(B)=13.2 in^{2}

Step-by-step explanation:

We begin with finding the angles a and b that from the drawing attached you can see that a=b.

Now, the sum of the internal angles of a rhomboid is equal to 360 degrees, with that we have:

120+120+a+b=360

240+2a=360

2a=120

a=60=b

Next, in the image you can see that the lines coming from the angle at the top 120 degrees vertex, divide the opposite sides by half, thus making two triangles with one side of 6 in and another of 3 in.

We can say from the drawing as well:

Area(A)+Area(B)+Area(C)=Area(rhomboid)

But, we can also say that Area(A)=Area(C)

So, starting with Area(A)

Area(A)=Area(triangle)=\frac{b*h}{2}=\frac{6*3}{2}=9 in^{2}

We can then calculate the area B, a rhomboid, or better, take the Total area of the figure and subtract the area of the two triangles.

Area(B)=Area(rhomboid)-Area(A)-Area(C)

Area(rhomboid)=b*h where b=6in and h is the perpendicular distance from the base to the top.

h=[tex]6*cos(30)=5.20in   The 30 degrees come from: 120-30-60=30, since the latitudes split the 120 angle in two equal parts and one that is the half of the obtuse angle.

Area(rhomboid)=5.20*6=31.2 in^{2}

Area(B)=Area(rhomboid)-Area(A)-Area(C)=31.2 in^{2}-9 in^{2}-9 in^{2}=13.2 in^{2}

3 0
3 years ago
7/10 ÷ 1/5 <br> pls i need help
blondinia [14]
7/10 ÷ 1/5 = 3 1/2 because if you just find the reciprocal of the second number (in this case 1/5) and then simply multiply the two numbers straight across after you find the reciprocal, you will need to convert and simplify as needed, and then you get your answer.
3 0
3 years ago
What integer best represents a gain of 5 gain
boyakko [2]
A gain in yards would be positive, therefore the best representation of a gain of five yards would be 5.

8 0
3 years ago
A store is having a sale on chocolate chips and walnuts. For 3 pounds of chocolate chips and 5 pounds of walnuts, the total cost
umka21 [38]

c = cost per pound of chocolate chips

w = cost per pound of walnuts.

\bf \stackrel{\textit{3 lbs of "c"}}{3c}+\stackrel{\textit{5 lbs of "w"}}{5w}~~=~~\stackrel{\textit{costs}}{15} \\\\\\ \stackrel{\textit{12 lbs of "c"}}{12c}+\stackrel{\textit{2 lbs of "w"}}{2w}~~=~~\stackrel{\textit{costs}}{33} \end{cases}\qquad \impliedby \textit{let's use elimination} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{llccccccl} 3c+5w=15&\times (-4)\implies &-12c&+&-20w&=&-60\\ 12c+2w=33&&12c&+&2w&=&33\\ \cline{3-7}\\ &&0&&-18w&=&-27 \end{array}

\bf -18w=-27\implies w=\cfrac{-27}{-18}\implies \blacktriangleright w=\cfrac{3}{2} \blacktriangleleft \\\\\\ \stackrel{\textit{substituting on the 1st equation}}{3c+5\left(\cfrac{3}{2} \right)=15}\implies 3c+\cfrac{15}{2}=15 \implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2\left( 3c+\cfrac{15}{2} \right)=2(15)} \\\\\\ 6c+15=30\implies 6c=15\implies c=\cfrac{15}{6}\implies \blacktriangleright c=\cfrac{5}{2} \blacktriangleleft

6 0
3 years ago
13 = 5 + 3b - 13<br><br> show work explained
IrinaVladis [17]
13 = 5 + 3b - 13\\&#10;3b=21\\&#10;b=7
8 0
3 years ago
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