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Norma-Jean [14]
3 years ago
5

Find the circumference of a circle with radius, r = 16.5m. Give your answer in terms of pi.

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
7 0

Answer:

103.714 approximately 104

Step-by-step explanation:

2^r

2 × 22/7 ×16.5

quester [9]3 years ago
6 0

Answer:

33π is the answer in terms of pi.

Step-by-step explanation:

Circumference of circle formula is C=πd.

Plug in the given values. We put 33 into d, because d represents diameter, and diameter is twice the radius(16.5), so we multiply 16.5 by 2. So far we have C=(π)(33).

C=(π)(33)=33π

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Step-by-step explanation:

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Every shared point is a solution. Since there are infinitely many points on a line, and these lines share every point, there are infinitely many solutions.

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Suppose sin(a)=3/4
Amanda [17]

well, we know the sine, and we also know that we're on the II Quadrant, let's recall that on the II Quadrant sine is positive whilst cosine is negative.

\bf sin^2(\theta)+cos^2(\theta)=1~\hspace{10em} tan(\theta )=\cfrac{sin(\theta )}{cos(\theta )} \\\\[-0.35em] ~\dotfill\\\\ sin^2(a)+cos^2(a)=1\implies cos^2(a) = 1-sin^2(a) \\\\\\ cos^2(a) = 1-[sin(a)]^2\implies cos^2(a) = 1-\left( \cfrac{3}{4} \right)^2\implies cos^2(a) = 1-\cfrac{3^2}{4^2} \\\\\\ cos^2(a) = 1-\cfrac{9}{16}\implies cos^2(a) = \cfrac{7}{16}\implies cos(a)=\pm\sqrt{\cfrac{7}{16}}

\bf cos(a)=\pm\cfrac{\sqrt{7}}{\sqrt{16}}\implies cos(a)=\pm\cfrac{\sqrt{7}}{4}\implies \stackrel{\textit{on the II Quadrant}}{cos(a)=-\cfrac{\sqrt{7}}{4}}\\\\[-0.35em]~\dotfill\\\\tan(a)=\cfrac{sin(a)}{cos(a)}\implies tan(a)=\cfrac{~~\frac{3}{4}~~}{-\frac{\sqrt{7}}{4}}\implies tan(a)=\cfrac{3}{4}\cdot \cfrac{4}{-\sqrt{7}}\\\\\\tan(a)=-\cfrac{3}{\sqrt{7}}\implies \stackrel{\textit{rounded up}}{tan(a) = -1.13}

5 0
3 years ago
A is the point (70, -80) and B has coordinates (-58, 48) what is exact length of AB
Nina [5.8K]

Answer:

128\sqrt{2}  units

Step-by-step explanation:

We are given;

  • Coordinates of A (70, -80)
  • Coordinates of B (-58, 48)

We are required to calculate the length of AB

  • To determine the length of AB we are going to use the formula for getting magnitude;
  • Given, coordinates (x₁, y₁) and (x₂, y₂), then
  • Magnitude =√((x₂-x₁)²+(y₂-y₁)²)

Therefore;

Length = \sqrt{((48+80)^{2} +(-58-70)^2})

            =\sqrt{16384+16384}

            = \sqrt{16384*2}

            = \sqrt{16384} *\sqrt{2}

            = 128\sqrt{2}

Therefore, the exact length of AB is 128\sqrt{2}  units

3 0
3 years ago
X y
wlad13 [49]

The best fit curve for #1 is D. The easiest way to check these is by pluggin in to the equation and seeing if they come close. By doing just the first ordered pair along, it is apparent that only D will work.

With x = 1 input

A) -36

B) 24.2

C) 17.5

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#2 is also D. We can tell this because multiplying any of these options always results in a middle term between them. For instance, if you multiply out C, you will not only get x^4 and x^4, but you will also get terms such as 4x^2y^2 in the middle.

3 0
3 years ago
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