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3 years ago

Write the number marked with an arrow on the number line below as an improper (top-heavy) fraction.

Mathematics

2 answers:

Amiraneli [1.4K]3 years ago

7 0

The answer is 33-5 !!

IrinaK [193]3 years ago

6 0

<h3>Answer: 33/5</h3>

===============================================

Explanation:

Start at 6 and count the small tickmarks to see that it takes 5 spaces to go from 6 to 7 on the number line.

So each small tickmark represents 1/5 of a unit.

The arrow is 3 ticks away from the 6, so we add on 3/5 to 6 getting the mixed number 6 + 3/5 = 6 & 3/5

The 6 is the whole part, while 3/5 is the fractional part.

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Let's convert to an improper fraction

6 & 3/5 = 6 + 3/5

6 & 3/5 = 6*(5/5) + 3/5

6 & 3/5 = 30/5 + 3/5

6 & 3/5 = (30+3)/5

6 & 3/5 = 33/5

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You could also use the formula

a & b/c = (a*c + b)/c

to get

6 & 3/5 = (6*5 + 3)/5

6 & 3/5 = 33/5

You might be interested in

Four times a number added to 3 times a larger number is 31. Seven subtracted from the larger number is equal to twice the smalle

notka56 [123]

Answer:

Let x represent the smaller number and y represent the larger number

<u>For the first equation </u>

Four times a number added to 3 times a larger number is 31 is written as

4x + 3y = 31

Making y the subject we have

3y = - 4x + 31

Divide both sides by 3

That's

$y = - \frac{4}{3} x + \frac{31}{3}$

<u>For the second equation</u>

Seven subtracted from the larger number is equal to twice the smaller number is written as

y - 7 = 2x

Making y the subject

We have

Hope this helps you

7 0

3 years ago

Solve the equation X-4/2=10<br> X=24<br> X=22<br> X=29<br> X=39

natali 33 [55]

Well, the answer to this question is X = 24.
Glad I could help and have a fantastic day!
Also, can you please mark my answer as the brainliest answer?
Thanks.

6 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs.

Mashcka [7]

Answer:

Part 1) $-17\frac{8}{9}$ -----> $-6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}$

Part 2) $-15.11$ ------> $-12.48-(-2.99)-5.62$

Part 3) $-19\frac{8}{9}$ -----> $-19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})$

Part 4) $-201.65$ -----> $-353.92-(-283.56)-131.29$

Part 5) $74$ ------> $83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})$

Step-by-step explanation:

Part 1) we have

$-6\frac{4}{9}-3\frac{2}{9}-8\frac{2}{9}$

To calculate the subtraction convert the mixed numbers to an improper fractions

$6\frac{4}{9}=\frac{6*9+4}{9}=\frac{58}{9}$

$3\frac{2}{9}=\frac{3*9+2}{9}=\frac{29}{9}$

$8\frac{2}{9}=\frac{8*9+2}{9}=\frac{74}{9}$

substitute

$-\frac{58}{9}-\frac{29}{9}-\frac{74}{9}=-\frac{(58+29+74)}{9}=-\frac{161}{9}$

Convert to mixed number

$-\frac{161}{9}=-(\frac{153}{9}+\frac{8}{9})=-17\frac{8}{9}$

Part 2) we have

$-12.48-(-2.99)-5.62$

To calculate the subtraction eliminate the parenthesis first

$-12.48-(-2.99)-5.62=-12.48+2.99-5.62=-15.11$

Part 3) we have

$-19\frac{2}{9}-4\frac{1}{9}-(-3\frac{4}{9})$

To calculate the subtraction convert the mixed numbers to an improper fractions

$19\frac{2}{9}=\frac{19*9+2}{9}=\frac{173}{9}$

$4\frac{1}{9}=\frac{4*9+1}{9}=\frac{37}{9}$

$3\frac{4}{9}=\frac{3*9+4}{9}=\frac{31}{9}$

substitute

$-\frac{173}{9}-\frac{37}{9}-(-\frac{31}{9})$

Eliminate the parenthesis

$-\frac{173}{9}-\frac{37}{9}+\frac{31}{9}=\frac{(-173-37+31)}{9}=-\frac{179}{9}$

Convert to mixed number

$-\frac{179}{9}=-(\frac{171}{9}+\frac{8}{9})=-19\frac{8}{9}$

Part 4) we have

$-353.92-(-283.56)-131.29$

To calculate the subtraction eliminate the parenthesis first

$-353.92+283.56-131.29=-201.65$

Part 5) we have

$83\frac{1}{5}-108\frac{2}{5}-(-99\frac{1}{5})$

To calculate the subtraction convert the mixed numbers to an improper fractions

$83\frac{1}{5}=\frac{83*5+1}{5}=\frac{416}{5}$

$108\frac{2}{5}=\frac{108*5+2}{5}=\frac{542}{5}$

$99\frac{1}{5}=\frac{99*5+1}{5}=\frac{496}{5}$

substitute

$\frac{416}{5}-\frac{542}{5}-(-\frac{496}{5})$

Eliminate the parenthesis

$\frac{416}{5}-\frac{542}{5}+\frac{496}{5}=\frac{(416-542+496)}{5}=\frac{370}{5}=74$

3 0

3 years ago

Sam kept track of the number of problems he was assigned for his math homework on the box plot.

yulyashka [42]

Answer:

Statement A is correct about Sam's box and whisker plot.

Step-by-step explanation:

We have been given a box plot and we are asked to find out true statement according to the box plot.

Since we know data represented by box plot is divided in four equal parts.

Upon looking at our box plot we can see that our data is symmetric. It's median is 15, which means half the math assignments have less than 15 problems and half of the math assignments have more than 15 problems.

Interquartile range represents 50% values of data and it is the difference between upper quartile and lower quartile. IQR is not affected by outliers.

$IQR=Q_3-Q_1$

Upon substituting given values from box plot we get,

$IQR=19-11=8$

From IQR we can conclude that half of the assignments contained 15 problems or fewer.Therefore, option A is the correct choice.

4 0

3 years ago

Read 2 more answers

PLEASE HELPPP!! A box contains only black and white chips There are 8 black chips and 6 white chips How many white chips must be

Law Incorporation [45]

Lets take away 2 white chips...

8 black and 4 white...total of 12 chips
P(black) = 8/12 = 2/3

remove 2 white chips <==

3 0

3 years ago