Which is greater 1.831 or 1.381?

Which problem can gingivitis lead to if left untreated?

andreev551 [17]

Answer:

Tooth infection

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Marshall left home biking at a constant rate of 20 mph. One hour later, it looked like it may rain, so his friend, Brett, set ou

xxTIMURxx [149]

Answer:

First, we need to find how far ahead Marshall was. Since he had been biking at 20 mph for one hour, he had gone 20 miles.

Next, we need to find how long it will take Brett to catch up to Marshall. In order to do this, we need to find how much faster Brett is going than Marshall. We do this by subtracting Marshall's speed from Brett's speed.

60 - 20 = 40. So, Brett is catching up to Marshall at 40 mph. Now, we figure out how long it will take for someone going 40 miles per hour to go 20 miles. We find this by dividing 40 miles per hour by 20. This is equal to 1/2 hour. So, it will take Brett 0.5 hours to catch up to Marshall. This is the same as A, so A is the correct answer.

We can check our answer by seeing how far Marshall and Brett will have gone. Marshall will have been biking for 1.5 hours, so we multiply 20 * 1.5 = 30. Marshall went 30 miles.

Brett drove for .5 hours at 60 mph, so he went 30 miles. Since Brett and Marshall went the same distance, our answer is correct.

4 0

3 years ago

You have 6 dollars +12 pennies +to quarters + 4 dimes=2 nickels how much do you have

alina1380 [7]

You may have $26 I not a genius but this is easy

3 0

3 years ago

D) - 15/3 = x + 1 how do i solve this

kobusy [5.1K]

Answer:

x = - 6

Step-by-step explanation:

- 15/3 = x + 1

- x = 1 + 15/3

- x = 3/3 + 15/3

- x = 18/3

x = - 18/3

x = - 6

6 0

3 years ago

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of days an

solniwko [45]

Answer:

(a) 283 days

(b) 248 days

Step-by-step explanation:

The complete question is:

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. (a) What is the minimum pregnancy length that can be in the top 11% of pregnancy lengths? (b) What is the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths?

Solution:

The random variable X can be defined as the pregnancy length in days.

Then, from the provided information $X\sim N(\mu=268, \sigma^{2}=12^{2})$ .

(a)

The minimum pregnancy length that can be in the top 11% of pregnancy lengths implies that:

P (X > x) = 0.11

⇒ P (Z > z) = 0.11

⇒ z = 1.23

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\\\1.23=\frac{x-268}{12}\\\\x=268+(12\times 1.23)\\\\x=282.76\\\\x\approx 283$

Thus, the minimum pregnancy length that can be in the top 11% of pregnancy lengths is 283 days.

(b)

The maximum pregnancy length that can be in the bottom 5% of pregnancy lengths implies that:

P (X < x) = 0.05

⇒ P (Z < z) = 0.05

⇒ z = -1.645

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\\\-1.645=\frac{x-268}{12}\\\\x=268-(12\times 1.645)\\\\x=248.26\\\\x\approx 248$

Thus, the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths is 248 days.

8 0

2 years ago

Which is greater 1.831 or 1.381?​

Which is greater 1.831 or 1.381?