393216 times 4 because you could continue it on until u get to nine
If altogether they spent a total of $71, and a cap cost $5, then the price of a t-shirt is $8. Option A is correct
From the question, we are told that all caps cost $5 each
Let the cost of each shirt be x:
If Andy bought a t-shirt and a cap for each of his six friends, there will be 6 shirts and 6 caps
If <u>Bob returned two caps and two t-shirts</u>, there will be 4 caps and 4 shirts left
If <u>Carl bought three t-shirts and returned a cap,</u> the number of caps remaining will be 3 caps and the number of shirts remaining will be 7 shirts
If they spent a total of $71, this means;
3(5) + 7x = 71
15 + 7x = 71
7x = 71 - 15
7x = 56
x = 56/7
x = 8
This shows that the price of a t-shirt is $8
Learn more here: brainly.com/question/16510024
Let x be the amount of cocoa you use in the recipe.
then 4x is the amount of flour used, and 5x is the amount sugar used.
x+4x+5x= 550g
10x=550g
x=55g
So, you use 55g of cocoa, 220g of flour, and 275g of sugar.
hope this helps! :)
I've answered your other question as well.
Step-by-step explanation:
Since the identity is true whether the angle x is measured in degrees, radians, gradians (indeed, anything else you care to concoct), I’ll omit the ‘degrees’ sign.
Using the binomial theorem, (a+b)3=a3+3a2b+3ab2+b3
⇒a3+b3=(a+b)3−3a2b−3ab2=(a+b)3−3(a+b)ab
Substituting a=sin2(x) and b=cos2(x), we have:
sin6(x)+cos6(x)=(sin2(x)+cos2(x))3−3(sin2(x)+cos2(x))sin2(x)cos2(x)
Using the trigonometric identity cos2(x)+sin2(x)=1, your expression simplifies to:
sin6(x)+cos6(x)=1−3sin2(x)cos2(x)
From the double angle formula for the sine function, sin(2x)=2sin(x)cos(x)⇒sin(x)cos(x)=0.5sin(2x)
Meaning the expression can be rewritten as:
sin6(x)+cos6(x)=1−0.75sin2(2x)=1−34sin2(2x)
Answer:

Step-by-step explanation:
multiply the numerator/denominator of the first fraction by (x - 4)
multiply the numerator/denominator of the second fraction by (x + 2)
this ensures that the fractions have a common denominator
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← subtract numerators leaving the common denominator
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