<BOA = 360 -250 = 110
<<span>BDA = 110/2 = 55
<</span><span>BCA = 360 - (90+90+110)
</span><<span>BCA = 360 - 290
<</span><span>BCA = 70</span>
We have a circle of radius 5 m inside a square of side 10 m. The shaded area is:

Now, we calculate the area of the square and the circle:

Finally, the shaded area is:
....................................................................................
Answer:
2/b
Step-by-step explanation:
a/b=3b
a=3b*b
a=3b^2
6b/a=6b/(3b^2)=2/b
F(x)=2sin(1/2x) is the answer