Answer:
165km
Step-by-step explanation:
If Gina leaves now and drives at 66km/h she will reach Alton just in time for her appointment
Now:
Distance=Speed X Time
D=66 X t=66t.....(I)
If she leaves in 40 minutes,and she must get there at the same time, her new drive time will be:
t hours - 40 minutes
=(t-40/60)hours=( t-2/3) hours
Her Distance this time
D=90(t-2/3)=90t-60.....(ii)
Since the distance to Alton does not change, we equate (I) and (ii)
66t=90t-60
60=90t-66t
60=24t
t=2.5 hours
From equation (I)
Distance=66t=66X2.5=165km
Distance to Alton is 165km.
If i was a tennis player playing in wimbledon i would break that rule ;-;
Based on the numbers we have we can assume that she saves 3 times more each week than the last (1*3=3, 3*3=9).
Following this trend we would multiply the amount she saved the third week ($9) by 3 to get $27 for the fourth week.
Then, we would multiply the amount she saved the fourth week ($27) by 3 to get $81 for the fifth week.
Finally, to figure out how much she saved in the 5 weeks, we need to add each value up to get 1+3+9+27+81= $121 saved in 5 weeks
They arent congruent when you look at the side lengths and area
Answer:
The answer is (g°f)(-1) = 27
Step-by-step explanation:
* (g°f)(1) ⇒ means make the domain of g is the range of f
- At first find the value of f(-1)
- Take the answer and substitute it as the value of x for g
- So the range of f is the domain of g
∵ f(x) = 4x + 7
∵ The domain of f = -1 ⇒ x is the domain
∴ f(-1) = 4(-1) + 7 = -4 + 7 = 3 ⇒ f(-1) is the range
∵ g(x) = x³
∵ x = f(-1) = 3 ⇒ the domain of g
∴ g(3) = 3³ = 27 ⇒ the range of g
* (g°f)(-1) = 27
