The triangle that must appear to be obtuse mmust have one of its angle to be greater than 90 but less than 180 degrees:
<h3>What are obtuse triangles?</h3>
Obtuse triangles are triangles that has one of theor angles to greater than 90 degrees.
Most obtuse triangles has two acute angles (angles less than 90 degrees) and a obtuse angle (angles between 90 and 180 degrees)
Hence the triangle that must appear to be obtuse mmust have one of its angle to be greater than 90 but less than 180 degrees:
Learn more on obtuse triangle here: brainly.com/question/3250447
Answer: SOMEONE LITERALLY ASKED ME THIS YESTERDAY. Also, the answer is t-3<26
Step-by-step explanation:
Just convert it into numbers.
6×7=42 so the number missing is 42
Answer and Step-by-step explanation:
(a) Given that x and y is even, we want to prove that xy is also even.
For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.
(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:
Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.
(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.
