Answer:

Step-by-step explanation:
Let the numerator of the fraction=x
Since the denominator of a fraction is two more than the numerator.
Denominator=x+2
The fraction is therefore:

If both numerator and denominator are decreased by six, the fraction becomes:

The simplified result is 
Therefore:

Substituting x=40 into the initial fraction

Therefore, the original fraction is 
suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?
Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.
Mean = 177
standard deviation = 26
We find z-score using given mean and standard deviation
z = 
= 
=-0.11538
Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)
= 0.5438
P(weight will be greater than 174 lb) = 0.5438
2x + y = x - y - 3 = 6
Add 3 to everything
2x + y + 3 = x - y - 3 + 3 = 6 + 3
2x + y + 3 = x - y = 9
2x + y + 3 = 9
2x + y = 6 = x - y
Add y to everything
2x + 2y = 6 + y = x
Since x = 6 + y substitute every x with 6 + y
2(6 + y) + 2y = x
12 + 4y = x
This is as simplified as I can get and then just place 12 + 4y into every x in the original problem then solve
Answer: C -1
calculate it from i and imaginary numbers