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Stels [109]
3 years ago
14

Test 21,753 for divisibility by 2, 3, 5, 9, and 10.

Mathematics
1 answer:
geniusboy [140]3 years ago
7 0

Answer:

21,753 is divisible by 3 and 9

Step-by-step explanation:

A number is  divisible by 2 if last digit of a number is 0, 2, 4 ,6 ,8

A number is  divisible by 3 if sum of digits is divisible by 3.

A number is  divisible by 5 if last digit of a number is 0 or 5

A number is  divisible by 9 if sum of digits is divisible by 9

A number is  divisible by 10 if last digit is 0.

So,  according to these rules  option (a) 3 ,9 is correct

Therefore , 21,753 is divisible by 3 and 9.          

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