Answer:x+-3
Step-by-step explanation:
-6x+21-3
-6x=18
Answer: b. 8.56 to 21.44
Step-by-step explanation:
Let be the mean number of pushups that can be done.
As per given , we have
Sample size : n= 10
Degree of freedom = n-1=9
Sample mean :
Sample standard deviation :
Significance level : α=1-0.95=0.05
From t- distribution table ,
Critical two -tailed t-value for α=0.05 and df = 9 is
Confidence interval for is given by :-
Hence, the 95% confidence interval for the true mean number of pushups that can be done is 8.56 to 21.44.
t=2w-1
OPTION A is the correct answer...