√x + x+13 =? domain

1 answer:

7 0

$\sqrt{x}+x+13}\\\\\sqrt{x}\ exist\ for\ x\geq0.\\\\Therefore\ the\ domain:\\\\x\geq0\to x\in\mathbb{R^+}\cup\{0\}\to x\in\left[0,\ \infty\right)$

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Answer:

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Step-by-step explanation:

Since the triangles are right triangles with 60 and 45 degree angles, their side lengths follow special triangles.

A 45-45-90 right triangle has side lengths $1-1-\sqrt{2}$ .

A 30-60-90 right triangle has side lengths $1 - \sqrt{3} -2$ .

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