3 years ago

√x + x+13 =? domain

1 answer:

7 0

$\sqrt{x}+x+13}\\\\\sqrt{x}\ exist\ for\ x\geq0.\\\\Therefore\ the\ domain:\\\\x\geq0\to x\in\mathbb{R^+}\cup\{0\}\to x\in\left[0,\ \infty\right)$

You might be interested in

Given that f(x) = 2x − 5, find the value of x that makes f(x) = 15.

Vladimir79 [104]

Answer:

Step-by-step explanation:

so you replace all the x's with 15 and it becomes

2×15-5

2×15=30

30-5=25

8 0

3 years ago

MULTIPLE CHOICE QUESTION

frosja888 [35]

Answer:

Step-by-step explanation:

11 and 12

8 0

3 years ago

-90 = -100 + x help need answer

d1i1m1o1n [39]

Answer:

10 =x

Step-by-step explanation:

-90 = -100 + x

Add 100 to each side to isolate x

-90+100 = -100+100 + x

10 =x

4 0

2 years ago

Witch is greater 4 cups or 2 quarts

mario62 [17]

2 quarts because 4 cups only goes into 1 quart and 2 quarts is a greater number then 1 so 2 quarts

8 0

3 years ago

Find the value of x in 4:x::x:16

AnnyKZ [126]

Given:

4:x::x:16

To find:

The value of x.

Solution:

We have,

4:x::x:16

It means, we have

4:x = x:16

It can be rewritten as

$\dfrac{4}{x}=\dfrac{x}{16}$

On cross multiplication, we get

$4\times 16=x\times x$

$64=x^2$

Taking square root on both sides.

$\pm \sqrt{64}=x$

$\pm 8=x$

Since ratio can be negative or positive, therefore, the value of x is either -8 or 8.

4 0

3 years ago