Find the area of the square whose length is 3.5 inches?

Mathematics

2 answers:

Lerok [7]3 years ago

4 0

Answer:

$12.25$

Step-by-step explanation:

Area of square is

${s}^{2}$

where s is the side length.

3.5 is s so the answer is

$3.5 {}^{2} = 12.25$

Vinvika [58]3 years ago

3 0

Answer:

Area = 12.25 square inches

Step-by-step explanation:

$Given \ length \ of \ a \ side \ of \ the \ square = 3.5 \ inches \\ \\Area \ of \ a \sqaure \ = side \times side = 3. 5 \times 3.5 = 12.25 \ in^2$

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How does the graph of f(x) =-3^2x-4 differ from the graph of g(x)=-3^2x

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$\bf ~~~~~~~~~~~~\textit{function transformations}
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$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
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with that template in mind, let's check,

$\bf f(x)=-3^{\stackrel{B}{2}x\stackrel{C}{-4}}\qquad \qquad g(x)=-3^{2x}\implies g(x)=-3^{\stackrel{B}{2}x\stackrel{C}{+0}}$

notice, g(x) has a horizontal shift of C/B or +0/2, or just 0, none.

while f(x) has a horizontal shift of C/B or -4/2, or -2, to the right.

so f(x) is really just g(x), but shifted horizontally over 2 units to the right.

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