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3 years ago

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two friends, Bob and Ben , each buy one lottery ticket. Each ticket contains six numbers from a total of 100 numbers (0-99). But

uses the numbers 1,2, 3, 4, 5, 6, and Ben chooses the numbers 39, 45, 66, 72, 74, 89. Who has a higher probability of winning

1 answer:

Anastaziya [24]3 years ago

7 0

I would say Ben because the chance of the numbers being 1,2,3,4,5, 6 would be extremely low

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Please answer fast!!!!!

BlackZzzverrR [31]

Answer:

x = 2

Step-by-step explanation:

note that 4096 = $8^{4}$ , then

$8^{2x}$ = $8^{4}$

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2 years ago

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Find the midpoint of the line segment joining the points. (6, -5), (6, 3)

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Answer:

The mid point is (6,-1)

Step-by-step explanation:

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Darina [25.2K]

The graph of the equations was plotted using geogebra graphing and attached.

Let x represent the hours weightlifting and y represent the hours doing cardio exercises.

Since he spend a maximum of 20 hours, hence:

x + y ≤ 20 (1)

Also, he spends at least 8 of those hours weightlifting, hence:

x ≥ 8 (2)

He wants to spend no more than 15 hours doing cardio exercises, this is:

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Find out more at: brainly.com/question/17178834

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2 years ago

An experiment consists of choosing objects without regards to order. Determine the size of the sample space when you choose the

sdas [7]

Answer:

a

$n= 75, 582$

b

$n= 2300$

c

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Step-by-step explanation:

Generally the size of the sample sample space is mathematically represented as

$n = \left N } \atop {}} \right. C_r$

Where N is the total number of objects available and r is the number of objects to be selected

So for a, where N = 19 and r = 8

$n = \left 19 } \atop {}} \right. C_8 = \frac{19 !}{(19 - 8 )! 8!}$

$= \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}$

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For b Where N = 25 and r = 3

$n = \left 25 } \atop {}} \right. C_3 = \frac{25 !}{(19 - 3 )! 3!}$

$= \frac{25 *24 *23 *22 ! }{22 ! \ 3!}$

$n= 2300$

For c Where N = 23 and r = 2

$n = \left 23 } \atop {}} \right. C_2 = \frac{23 !}{(23 - 2 )! 2!}$

$= \frac{23 *22 *21! }{21 ! \ 3!}$

$n = 253$

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3 years ago

Simply the expression 2(10)+2(x+4)

postnew [5]

Step-by-step explanation:

2(10)+2(x+4)

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