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3 years ago

The table below shows field goal statistics for three different kickers.

Mathematics

2 answers:

balu736 [363]3 years ago

4 0

Answer:

cba

Step-by-step explanation:

Ratling [72]3 years ago

3 0

Answer: Kicker C, kicker B, and then kicker A

Step-by-step explanation:

divide the field goals made by field goals attempted to get the success rate. A = 12 / 14 = 0.857 B = 15 / 18 = 0.83 C = 19 / 24 = 0.79

0.79 < 0.83 < 0.857

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Perform the indicated operation of <br>4.2+1.9

kykrilka [37]

Answer:

6.1

Step-by-step explanation:

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4 0

3 years ago

Ben works for software company in Cleveland. To train new employees, Ben travels to their two other locations, Buffalo and Phila

Andru [333]

Answer:

Explanation:we will solve this question with help of linear programming.

Now, let Ben goes x times in buffalo trip and goes y times in Philadelphia trip. Thus, according to the question, Min Z= 180x+300y

And s.t.r. 2x+3y≤105, where x≥5, y≥15.

since at (0,0) 0≤105(true), so area of 2x+3y≤105 will cover the origin.

But, 0≥5 and 0≥15 are false, so their area will not cover the origin.

Thus, after drawing the graph of these three lines we will get a feasible reason of triangle ABC, where point A≡(5,31.667), B≡(5,15), and C≡(30,15)

Z at A- 180×5+300×31.667=10,400.1

at B-180×5+300×15=1350( which is minimum.)

at C- 180×30+300×15=5,850

Thus, Ben should go 5 times to buffalo trip and 15 times to Philadelphia to minimize his cost which is $1350.

3 0

4 years ago

If ADEF is reflected over the x-axis, what would be the coordinates of point F?

Brut [27]

Answer:

Please check the explanation.

Step-by-step explanation:

Let the coordinates of the point F be (x, y).

When a point F(x, y) is reflected over the x-axis, the x-coordinate of the point F remains the same, and the y-coordinate of the point reverses the sign.

Thus, the rule of reflection over the x-axis:

F(x, y) → F'(x, -y)

Here,

F'(x, -y) would be coordinates of point F after the reflection over the x-axis.

Let say, the point F(1, 2).

The coordinate of the point F after the reflection over the x-axis would be:

F(1, 2) → F'(1, -2)

Thus, F'(1, -2) would be the coordinates of point F after the reflection over the x-axis.

6 0

3 years ago

OOOO

lbvjy [14]

Step-by-step explanation:

Given bi-quadratic equation is:

$x^4+95x^2 -500=0$

Substituting $x^2=a,$ given bi-quadratic equation reduces in the form of following quadratic equation:

$a^2 +95a -500=0\\$

Let us factorize the above quadratic equation:

$a^2 +95a -500=0\\\therefore\: a^2 +100a -5a-500=0\\\therefore\: a(a +100) -5(a+100)=0\\\therefore\: (a +100)(a -5)=0\\\therefore\: (a +100)=0\:\: or \:\: (a -5)=0\\\therefore\: a = - 100\:\: or \:\: a = 5\\\\CASE\: (1)\:\\When\: a = - 100 \implies x^2 = - 100\\\therefore x=\pm \sqrt{-100}\\$